假设我有一个代码,它要求用户提供一些输入,如下所示：
for (condition) {
System.out.println("Please give some input");
System.in.read();
} //lets say this loop repeats 3 times and i face a problem during second iteration
但我想给用户一个60秒的时间限制,然后抛出一个异常(在这种情况下,我认为它的TimeOutException).我怎么做？
解决方法
import java.util.Timer;
import java.util.TimerTask;
import java.io.*;
public class test
{
private String str = "";
TimerTask task = new TimerTask()
{
public void run()
{
if( str.equals("") )
{
System.out.println( "you input nothing. exit..." );
System.exit( 0 );
}
}
};
public void getInput() throws Exception
{
Timer timer = new Timer();
timer.schedule( task,10*1000 );
System.out.println( "Input a string within 10 seconds: " );
BufferedReader in = new BufferedReader(
new InputStreamReader( System.in ) );
str = in.readLine();
timer.cancel();
System.out.println( "you have entered: "+ str );
}
public static void main( String[] args )
{
try
{
(new test()).getInput();
}
catch( Exception e )
{
System.out.println( e );
}
System.out.println( "main exit..." );
}
}
