但是数据结构太糟糕了,如果我像MD C一样在MDetail中包含一个新的数据类,比如ScreenDef,那么所有旧的代码都必须重写.

对于包含某些类的复杂类,是否有良好的数据结构？我希望将来数据构建可以轻松扩展！

代码A.

data class BluetoothDef(val Status:Boolean=false)
data class WiFiDef(val Name:String,val Status:Boolean=false)

data class MDetail (
        val _id: Long,val bluetooth: BluetoothDef,val wiFi:WiFiDef
)

代码B.

var mBluetoothDef1= BluetoothDef()
var mWiFiDef1= WiFiHelper(this).getWiFiDefFromSystem()
var aMDetail1= MDetail(7L,mBluetoothDef1,mWiFiDef1)

代码C.

data class BluetoothDef(val Status:Boolean=false)
data class WiFiDef(val Name:String,val Status:Boolean=false)
data class ScreenDef(val Name:String,val size:Long)
... 

data class MDetail (
        val _id: Long,val wiFi:WiFiDef
        val aScreenDef:ScreenDef        
        ...
)

以下代码基于s1m0nw1所说的内容,我认为将来很容易扩展.谢谢！

还有其他更好的方法吗？

版本1代码

interface DeviceDef

data class BluetoothDef(val Status: Boolean = false) : DeviceDef
data class WiFiDef(val Name: String,val Status: Boolean = false) : DeviceDef
data class ScreenDef(val Name: String,val size: Long) : DeviceDef

class MDetail(val _id: Long,val devices: MutableList<DeviceDef>) {
    inline fun <reified T> getDevice(): T {
        return devices.filterIsInstance(T::class.java).first()
    }
}

class UIMain : AppCompatActivity() {

    override fun onCreate(savedInstanceState: Bundle?) {
        super.onCreate(savedInstanceState)
        setContentView(R.layout.layout_main)

        val btD = BluetoothDef(true)
        val wfD = WiFiDef("MyWifi")
        val xSc = ScreenDef("MyScreen",1)
        val m = MDetail(7L,mutableListOf(btD,wfD,xSc))


        handleBluetoothDef(m.getDevice<BluetoothDef>())
        handleWiFiDef(m.getDevice<WiFiDef>())
        handleScreenDef(m.getDevice<ScreenDef>())
    }

    fun handleBluetoothDef(mBluetoothDef:BluetoothDef){ }    
    fun handleWiFiDef(mWiFiDef:WiFiDef){ }    
    fun handleScreenDef(mScreenDef:ScreenDef){ }
}

版本2代码(扩展)

interface DeviceDef

data class BluetoothDef(val Status: Boolean = false) : DeviceDef
data class WiFiDef(val Name: String,val size: Long) : DeviceDef

data class TimeLine(val Name: String): DeviceDef  //Extend

class MDetail(val _id: Long,1)

        val aTe = TimeLine("MyTimeline")  //Extend

        val m = MDetail(7L,xSc,aTe)) //Modified


        handleBluetoothDef(m.getDevice<BluetoothDef>())
        handleWiFiDef(m.getDevice<WiFiDef>())
        handleScreenDef(m.getDevice<ScreenDef>())

        handleTimeLine(m.getDevice<TimeLine>()) //Extend
    }

    fun handleBluetoothDef(mBluetoothDef:BluetoothDef){}    
    fun handleWiFiDef(mWiFiDef:WiFiDef){ }    
    fun handleScreenDef(mScreenDef:ScreenDef){ }           
    fun handleTimeLine(mTimeLine:TimeLine){}  //Extend

救命

我必须用open类替换接口,因为我无法从json字符串GSON反序列化MDetail对象.

但有趣的内联乐趣< reified T> getDevice()：T {}无法返回正确的结果,我该怎么修改？谢谢！

open class DeviceDef

data class BluetoothDef(val status:Boolean=false):  DeviceDef()
data class WiFiDef(val name:String,val status:Boolean=false) : DeviceDef()

data class MDetail(val _id: Long,val deviceList: MutableList<DeviceDef>)
{
    inline fun <reified T> getDevice(): T {        
        return deviceList.filterIsInstance(T::class.java).first()
    }
}