<?PHP $str = "word <a href=\"word\">word</word>word word"; $str = preg_replace("/word(?!([^<]+)?>)/i","repl",$str); echo $str; # repl <word word="word">repl</word> ?>
来源：http://pureform.wordpress.com/2008/01/04/matching-a-word-characters-outside-of-html-tags/
不幸的是,我的项目需要一个仅适用于Java的语义库…
//谢谢Celso
解决方法@H_301_12@
使用String.replaceAll()方法：
class Test {
public static void main(String[] args) {
String str = "word <a href=\"word\">word</word>word word";
str = str.replaceAll("word(?!([^<]+)?>)","repl");
System.out.println(str);
}
}
希望这可以帮助.
class Test {
public static void main(String[] args) {
String str = "word <a href=\"word\">word</word>word word";
str = str.replaceAll("word(?!([^<]+)?>)","repl");
System.out.println(str);
}
}
希望这可以帮助.
