我有REST服务代码下面的代码返回一个文件,现在问题是在PostMan客户端的响应体中我得到一个原始响应,我怎么能转换它以便它向客户端显示文件的内容,目标是将文件返回给用户.File Name是“File1.jpeg”
码：
@RequestMapping(value = URIConstansts.GET_FILE,produces = { "application/json" },method = RequestMethod.GET)
public @ResponseBody ResponseEntity getFile(@RequestParam(value="fileName",required=false) String fileName,HttpServletRequest request) throws IOException{
ResponseEntity respEntity = null;
byte[] reportBytes = null;
File result=new File("/home/arpit/Documents/PCAP/dummyPath/"+fileName);
if(result.exists()){
InputStream inputStream = new FileInputStream("/home/arpit/Documents/PCAP/dummyPath/"+fileName);
byte[]out=org.apache.commons.io.IoUtils.toByteArray(inputStream);
HttpHeaders responseHeaders = new HttpHeaders();
responseHeaders.add("content-disposition","attachment; filename=" + fileName);
respEntity = new ResponseEntity(out,responseHeaders,HttpStatus.OK);
}else{
respEntity = new ResponseEntity ("File Not Found",HttpStatus.OK);
}
return respEntity;
}
解决方法
下面的代码解决了我的问题：
@RequestMapping(value = URIConstansts.GET_FILE,HttpServletRequest request) throws IOException{
ResponseEntity respEntity = null;
byte[] reportBytes = null;
File result=new File("/home/arpit/Documents/PCAP/dummyPath/"+fileName);
if(result.exists()){
InputStream inputStream = new FileInputStream("/home/arpit/Documents/PCAP/dummyPath/"+fileName);
String type=result.toURL().openConnection().guessContentTypeFromName(fileName);
byte[]out=org.apache.commons.io.IoUtils.toByteArray(inputStream);
HttpHeaders responseHeaders = new HttpHeaders();
responseHeaders.add("content-disposition","attachment; filename=" + fileName);
responseHeaders.add("Content-Type",type);
respEntity = new ResponseEntity(out,HttpStatus.OK);
}else{
respEntity = new ResponseEntity ("File Not Found",HttpStatus.OK);
}
return respEntity;
}
