我正在尝试
Java编程书中的几个练习.我有以下代码：
import java.io.*;
import java.util.Scanner;
public class Ex420
{
public static void main( String args[] )
{
String employeeName = "";
double workHours,excessHours,hourlyRates,grossPay;
Scanner input = new Scanner( System.in );
while ( employeeName != "stop" )
{
System.out.printf( "\nInput employee name or stop to exit: " );
employeeName = input.nextLine();
System.out.printf( "Input working hours: " );
workHours = input.nextDouble();
System.out.printf( "Input hourly rates: " );
hourlyRates = input.nextDouble();
if ( workHours <= 40 & workHours >= 0 )
{
excessHours = 0;
grossPay = hourlyRates * workHours;
System.out.printf( "%s's gross pay is $%.2f\n",employeeName,grossPay );
}
else if ( workHours > 40 )
{
excessHours = workHours - 40;
grossPay = hourlyRates * 40 + 1.5 * hourlyRates * excessHours;
System.out.printf( "\n%s's worked for %.1f excess hours.\n",excessHours );
System.out.printf( "%s's gross pay is $%.2f\n",grossPay );
}
else
{
System.out.printf( "Invalid input. Please try again." );
}
} // end while
} // end main
} // end class Ex420
问题是,while循环似乎不起作用.每当我输入“stop”作为employeeName时,程序就会继续.我尝试用任何其他字符串替换“停止”,它仍然无法正常工作.但是当我尝试使用“stop”初始化employeeName时,程序会立即退出,这是预期的.我在这做错了什么？
此外,在第一个循环之后,程序总是跳过询问employeeName.我尝试替换employeeName = input.nextLine(); with employeeName = input.next();它不再跳过它.我想知道,有什么办法可以让我在使用employeeName = input.nextLine()时不跳过输入;？
在此先感谢您的帮助！
