我的理解:
与JComponent.repaint()中Swing调用的大多数组件/操作不同,线程安全即使是从另一个线程(即不是从EDT)进行重新绘制请求,所以实际绘画仅在EDT中发生.以下代码片段演示了这一点.
与JComponent.repaint()中Swing调用的大多数组件/操作不同,线程安全即使是从另一个线程(即不是从EDT)进行重新绘制请求,所以实际绘画仅在EDT中发生.以下代码片段演示了这一点.
public class PaintingDemo { public static void main(String[] args) { final JFrame frame = new JFrame(); final JPanel p = new MyPanel(); SwingUtilities.invokeLater(new Runnable() { @Override public void run() { frame.add(p,BorderLayout.CENTER); frame.setSize(200,200); frame.setDefaultCloSEOperation(JFrame.EXIT_ON_CLOSE); frame.setVisible(true); } }); new Thread("MyThread") { public void run() { while (true) { // Below statements are important to show the difference p.repaint(); p.paintImmediately(p.getBounds()); try { Thread.sleep(1000); } catch(Exception e) {} } } }.start(); } } class MyPanel extends JPanel { @Override public void paint(Graphics g) { System.out.println("paint() called in "+ Thread.currentThread().getName()); super.paint(g); } }
从输出中可以看出,在调用repaint()时,在EDT中完成绘制,而不管调用哪个线程 – 所以没有问题.但是,在paintImmediately()的情况下 – 绘画发生在调用它的同一个线程中.
考虑一个情况是,EDT正在更改组件的状态,另一个线程(从中调用paintImmediately())正在绘制相同的组件.
我的问题:
在paintImmediately()的情况下,Event Dispatcher Thread(EDT)和其他线程之间的同步处理如何?
解决方法
据我了解,当您调用paintImmediately时,您调用以下代码:
Component c = this; Component parent; if(!isShowing()) { return; } JComponent paintingOigin = SwingUtilities.getPaintingOrigin(this); if (paintingOigin != null) { Rectangle rectangle = SwingUtilities.convertRectangle( c,new Rectangle(x,y,w,h),paintingOigin); paintingOigin.paintImmediately(rectangle.x,rectangle.y,rectangle.width,rectangle.height); return; } while(!c.isOpaque()) { parent = c.getParent(); if(parent != null) { x += c.getX(); y += c.getY(); c = parent; } else { break; } if(!(c instanceof JComponent)) { break; } } if(c instanceof JComponent) { ((JComponent)c)._paintImmediately(x,h); } else { c.repaint(x,h); }
所以,除非这不是一个JComponent,否则你最终会调用_paintImmediately(),最后调用paint(Graphics),建议下面的栈跟踪(从我将在这篇文章结尾发贴的一段代码中获取):
Thread [pool-1-thread-1] (Suspended) TestPaint$1.paint(Graphics) line: 23 TestPaint$1(JComponent).paintToOffscreen(Graphics,int,int) line: 5221 RepaintManager$PaintManager.paintDoubleBuffered(JComponent,Image,Graphics,int) line: 1482 RepaintManager$PaintManager.paint(JComponent,JComponent,int) line: 1413 RepaintManager.paint(JComponent,int) line: 1206 TestPaint$1(JComponent)._paintImmediately(int,int) line: 5169 TestPaint$1(JComponent).paintImmediately(int,int) line: 4980 TestPaint$1(JComponent).paintImmediately(Rectangle) line: 4992 TestPaint$3.run() line: 50 ThreadPoolExecutor.runWorker(ThreadPoolExecutor$Worker) line: 1110 ThreadPoolExecutor$Worker.run() line: 603 Thread.run() line: 722
但是如果您尝试同时调用repaint()(从另一个线程),您会看到它们同时运行(我尝试使用调试器执行代码并绘画从未停止在另一个线程中发生)似乎在Java代码级别,没有太多同步(至少我找不到任何东西).所以如果你最后在EDT中修改组件状态,我相信结果是不可预测的,你应该一定要避免这种情况.
为了说明我的观点,我尝试在paint方法中修改一个变量的状态,添加一个睡眠以增加2个线程(EDT和另一个线程)之间的冲突风险,并且它看起来似乎没有两者之间的同步线程(System.err.println()不时输出为null).
现在我想知道为什么你需要立即执行一个paint.除非你阻止EDT,否则没有太多有效的理由来执行这样的事情.
以下是我用来测试这些东西的代码(非常接近问题中的一个).代码只是为了尝试了解发生了什么,而不是展示如何执行正确的绘画或任何好的Swing练习.
import java.awt.Color; import java.awt.Graphics; import java.awt.event.ActionEvent; import java.awt.event.ActionListener; import java.util.Random; import java.util.concurrent.Executors; import javax.swing.JFrame; import javax.swing.JPanel; import javax.swing.SwingUtilities; import javax.swing.Timer; public class TestPaint { protected void initUI() { JFrame frame = new JFrame(); frame.setDefaultCloSEOperation(JFrame.EXIT_ON_CLOSE); frame.setTitle(TestPaint.class.getSimpleName()); final Random rand = new Random(); final JPanel comp = new JPanel() { private String value; @Override public void paint(Graphics g) { value = "hello"; super.paint(g); try { Thread.sleep(20); } catch (InterruptedException e) { // TODO Auto-generated catch block e.printStackTrace(); } g.setColor(new Color(rand.nextInt(256),rand.nextInt(256),rand.nextInt(256))); g.fillRect(0,getWidth(),getHeight()); if (SwingUtilities.isEventDispatchThread()) { System.err.println("Painting in the EDT " + getValue()); } else { System.err.println("Not painting in EDT " + getValue()); } value = null; } public String getValue() { return value; } }; frame.add(comp); frame.setSize(400,400); frame.setLocationRelativeTo(null); frame.setVisible(true); Timer t = new Timer(1,new ActionListener() { @Override public void actionPerformed(ActionEvent e) { comp.repaint(); } }); t.start(); Executors.newSingleThreadExecutor().execute(new Runnable() { @Override public void run() { while (true) { comp.paintImmediately(comp.getBounds()); } } }); } public static void main(String[] args) { SwingUtilities.invokeLater(new Runnable() { @Override public void run() { new TestPaint().initUI(); } }); } }