有没有任何开源工具或jar来处理
java中的反射？
例如：
class Department {
String name ;
Employee[] employees;
public void setName(String name) {
this.name = name;
}
public String getName() {
return name;
}
public Employee[] getEmployes() {
return employees;
}
}
我想打印所有的员工到控制台输出,而是在运行时如下所示：
Department dept = new Department(); // add employees.. getEmployeeNames(dept,"getEmployees.getAddress.getStreet"); // So the user says they want employee street,but we don't know that // until run-tme.
有什么反思的开源可以容纳这样的东西吗？
解决方法
当我看到这种事情总是会响起设计闹钟.
话虽如此,我通常认为JXPath(http://commons.apache.org/jxpath/users-guide.html)对于这种类型的问题来说是最合理的解决方案,如果不能以更加设计的方式解决问题：
import org.apache.commons.jxpath.JXPathContext;
import java.util.ArrayList;
import java.util.Iterator;
import java.util.List;
/**
*/
public class JXPather {
public static void main(String[] args) {
Department d = new Department();
d.employees.add(new Employee(new Address("wherever a")));
d.employees.add(new Employee(new Address("wherever b")));
d.employees.add(new Employee(new Address("wherever c")));
d.employees.add(new Employee(new Address("wherever def")));
JXPathContext context = JXPathContext.newContext(d);
// access matched xpath objects by iterating over them
for (Iterator iterator = context.iterate("/employees/address/street"); iterator.hasNext();) {
System.out.println(iterator.next());
}
// or directly via standard xpath expressions
System.out.println("street of third employee is: "+context.getValue("/employees[3]/address/street"));
// supports most (or all ?) xpath expressions
for (Iterator iterator = context.iterate("/employees/address/street[string-length(.) > 11]"); iterator.hasNext();) {
System.out.println("street length longer than 11 c'ars:"+iterator.next());
}
}
static public class Department {
List<Employee> employees = new ArrayList<Employee>();
public List<Employee> getEmployees() {
return employees;
}
}
static public class Employee {
Address address;
Employee(Address address) {
this.address = address;
}
public Address getAddress() {
return address;
}
}
static public class Address {
String street;
Address(String street) {
this.street = street;
}
public String getStreet() {
return street;
}
}
}
