when(candidateService.findById(1)).thenReturn(new Candidate());
我想扩展这种行为为任何整数(不一定为1)
如果我吃惊
when(candidateService.findById( any(Integer.class) )).thenReturn(new Candidate());
我有编译错误
The method findById(Integer) in the type CandidateService is not
applicable for the arguments (Matcher)
UPDATE
进口:
import static org.junit.Assert.assertEquals; import static org.mockito.Matchers.anyInt; import static org.mockito.Matchers.anyString; import static org.mockito.Mockito.mock; import static org.mockito.Mockito.times; import static org.mockito.Mockito.verify; import static org.mockito.Mockito.when; import static org.springframework.test.web.servlet.result.MockMvcResultMatchers.status; import java.util.ArrayList; import java.util.HashSet; import org.junit.Before; import org.junit.Test; import org.junit.runner.RunWith; import org.mockito.InjectMocks; import org.mockito.Mock; import org.mockito.MockitoAnnotations;
解决方法
尝试anyInt():
when(candidateService.findById( anyInt())).thenReturn(new Candidate());
例如我的项目中有anyLong():
when(dao.getAddress(anyLong())).thenReturn(Arrays.asList(dto));
编辑:
您必须导入:
import static org.mockito.Matchers.anyInt;