例如,我想要翻译某个节点a,以便它暂时与另一个节点b重叠.所以我希望将其translateX属性设置为b.globalX-a.globalX.

文件说：

Defines the X coordinate of the
translation that is added to the
transformed coordinates of this Node
for the purpose of layout. Containers
or Groups performing layout will set
this variable relative to
layoutBounds.minX in order to position
the node at the desired layout
location.

For example,if child should have a
final location of finalX:

child.layoutX = finalX - child.layoutBounds.minX;

也就是说,任何节点的最终坐标应该是

finalX = node.layoutX + node.layoutBounds.minX

但是运行以下代码：

var rect;
Stage {
    title: "Application title"
    width: 250
    height:250
    scene: Scene {
        content: [
            Stack{content:[rect = Rectangle { width:10 height:10}] layoutX:10}
        ]
    }
}

println("finalX = {rect.layoutX+rect.layoutBounds.minX}");

给我finalX = 0.0,而不是finalX = 10.0,因为文档看起来状态.

有没有一个明确的方法来获得JavaFX中绝对最终的定位坐标？