我正在设置一个按钮的可见性,如下所示:
public Bundle setActivityState(Bundle bundle){ startBtn = (Button) findViewById(R.id.startSensorsBtn); startBtn.setVisibility( getVisibilityState(bundle,PersistanceConstants.START_BTN_STATE) ); return bundle; } public int getVisibilityState(Bundle bundle,String keyName){ if (bundle.getInt(keyName) == View.VISIBLE){ return View.VISIBLE; } else if (bundle.getInt(keyName) == View.INVISIBLE){ return View.INVISIBLE; } else if (bundle.getInt(keyName) == View.GONE){ return View.GONE; } return 0; }
但我收到错误:
Must be one of: View.VISIBLE,View.INVISIBLE,View.GONE less... (Ctrl+F1) Reports two types of problems: - Supplying the wrong type of resource identifier. For example,when calling Resources.getString(int id),you should be passing R.string.something,not R.drawable.something. - Passing the wrong constant to a method which expects one of a specific set of constants. For example,when calling View#setLayoutDirection,the parameter must be android.view.View.LAYOUT_DIRECTION_LTR or android.view.View.LAYOUT_DIRECTION_RTL.
而打电话
getVisibilityState(bundle,PersistanceConstants.START_BTN_STATE)
我不知道如何解决这个问题.我明白,它期待一组给定的值,但我知道的只是传递一个int.这里可以做些什么?
@H_301_14@