我刚开始使用
java和libgdx,并且有这个代码,很简单,它会在屏幕上打印一个sprite.这样做完美,我从中学到了很多东西.
package com.MarioGame;
import com.badlogic.gdx.ApplicationListener;
import com.badlogic.gdx.Gdx;
import com.badlogic.gdx.files.FileHandle;
import com.badlogic.gdx.graphics.GL10;
import com.badlogic.gdx.graphics.Texture;
import com.badlogic.gdx.graphics.g2d.Sprite;
import com.badlogic.gdx.graphics.g2d.SpriteBatch;
import com.badlogic.gdx.graphics.g2d.TextureRegion;
import com.badlogic.gdx.InputProcessor;
public class Game implements ApplicationListener {
private SpriteBatch batch;
private Texture marioTexture;
private Sprite mario;
private int marioX;
private int marioY;
@Override
public void create() {
batch = new SpriteBatch();
FileHandle marioFileHandle = Gdx.files.internal("mario.png");
marioTexture = new Texture(marioFileHandle);
mario = new Sprite(marioTexture,158,32,64);
marioX = 0;
marioY = 0;
}
@Override
public void render() {
Gdx.gl.glClear(GL10.GL_COLOR_BUFFER_BIT);
batch.begin();
batch.draw(mario,marioX,marioY);
batch.end();
}
@Override
public void resume() {
}
@Override
public void resize(int width,int height) {
}
@Override
public void pause() {
}
@Override
public void dispose() {
}
}
解决方法
对于您手头的任务,您甚至可能不需要实现InputProcessor.你可以在这样的render()方法中使用Input.isKeyPressed()方法.
float marioSpeed = 10.0f; // 10 pixels per second.
float marioX;
float marioY;
public void render() {
if(Gdx.input.isKeyPressed(Keys.DPAD_LEFT))
marioX -= Gdx.graphics.getDeltaTime() * marioSpeed;
if(Gdx.input.isKeyPressed(Keys.DPAD_RIGHT))
marioX += Gdx.graphics.getDeltaTime() * marioSpeed;
if(Gdx.input.isKeyPressed(Keys.DPAD_UP))
marioY += Gdx.graphics.getDeltaTime() * marioSpeed;
if(Gdx.input.isKeyPressed(Keys.DPAD_DOWN))
marioY -= Gdx.graphics.getDeltaTime() * marioSpeed;
Gdx.gl.glClear(GL10.GL_COLOR_BUFFER_BIT);
batch.begin();
batch.draw(mario,(int)marioX,(int)marioY);
batch.end();
}
还要注意,我做了马里奥浮标的位置坐标,并将运动改为时间运动.马里奥速度是马里奥每秒向任何方向行进的像素数. Gdx.graphics.getDeltaTime()返回自上次调用render()以来的传递时间(以秒为单位).在大多数情况下,转换为int实际上并不是必需的.
Btw,我们在http://www.badlogicgames.com/forum的论坛,你也问libgdx的具体问题！
心连心,马里奥
