参见英文答案 >
Android how to sort JSONArray of JSONObjects6
如何按对象的字段排序对象的JSONArray？
如何按对象的字段排序对象的JSONArray？
输入：
[
{ "ID": "135","Name": "Fargo Chan" },{ "ID": "432","Name": "Aaron Luke" },{ "ID": "252","Name": "Dilip Singh" }
];
[
{ "ID": "432","Name": "Dilip Singh" }
{ "ID": "135",];
解决方法
尝试这个：
//I assume that we need to create a JSONArray object from the following string
String jsonArrStr = "[ { \"ID\": \"135\",\"Name\": \"Fargo Chan\" },{ \"ID\": \"432\",\"Name\": \"Aaron Luke\" },{ \"ID\": \"252\",\"Name\": \"Dilip Singh\" }]";
JSONArray jsonArr = new JSONArray(jsonArrStr);
JSONArray sortedJsonArray = new JSONArray();
List<JSONObject> jsonValues = new ArrayList<JSONObject>();
for (int i = 0; i < jsonArr.length(); i++) {
jsonValues.add(jsonArr.getJSONObject(i));
}
Collections.sort( jsonValues,new Comparator<JSONObject>() {
//You can change "Name" with "ID" if you want to sort by ID
private static final String KEY_NAME = "Name";
@Override
public int compare(JSONObject a,JSONObject b) {
String valA = new String();
String valB = new String();
try {
valA = (String) a.get(KEY_NAME);
valB = (String) b.get(KEY_NAME);
}
catch (JSONException e) {
//do something
}
return valA.compareTo(valB);
//if you want to change the sort order,simply use the following:
//return -valA.compareTo(valB);
}
});
for (int i = 0; i < jsonArr.length(); i++) {
sortedJsonArray.put(jsonValues.get(i));
}
排序的JSONArray现在存储在sortedJsonArray对象中.
