为什么在尝试执行异步脚本时会收到硒2.25.0的异常.
//navigate to my test page.
String script = "var callback = arguments[arguments.length - 1];" +
"getResult(callback)";
Object result = ((JavascriptExecutor)driver).executeAsyncScript(script,"");
System.out.println(result);
测试页面包含以下脚本：
var result = true;
function getResult(callback){
window.setTimeout(function(){callback(true);},3000);
}
这引发了一个例外：
Failed: testSeleniumAsync org.openqa.selenium.TimeoutException: Script execution Failed. Script: var callback = arguments[arguments.length - 1];getResult(callback); Timed out waiting for asyncrhonous script result after 2 ms (WARNING: The server did not provide any stacktrace information) Command duration or timeout: 11 milliseconds Build info: version: '2.25.0',revision: '17482',time: '2012-07-18 22:18:01' System info: os.name: 'Linux',os.arch: 'amd64',os.version: '3.2.0-27-generic',java.version: '1.6.0_26' Driver info: driver.version: RemoteWebDriver Session ID: 6347b507cf22b6c2d3312937a82a0a02 at sun.reflect.NativeConstructorAccessorImpl.newInstance0(Native Method) at sun.reflect.NativeConstructorAccessorImpl.newInstance(NativeConstructorAccessorImpl.java:39) at sun.reflect.DelegatingConstructorAccessorImpl.newInstance(DelegatingConstructorAccessorImpl.java:27)
如果我从我的脚本中删除setTimeout,并且我调用回调,它可以工作.但这不是我想要的.
谢谢.
解决方法
它非常奇怪,API在2 ms内超时.
我猜测脚本超时是以某种方式配置不正确(< = 0sec).由于您的窗口超时发生在3秒钟之后,请尝试将脚本超时设置为大于3秒的值,然后再进行通话. 像这样：
driver.manage().timeouts().setScriptTimeout(5,TimeUnit.SECONDS);
这可能会起作用
