java – 异常捕获但程序不断运行

我正在开展我的第一个 Java项目,实施一个名为“HeartRates”的课程,该课程取得用户的出生日期,并返回其最大和目标心率.主要测试程序中的一切工作除了一件事之外,我无法弄清楚在异常被捕获后如何停止打印其余的代码.

我不太确定代码中的异常被捕获的全部部分,因为它是由教授给我们复制和粘贴的.如果任何人可以告诉我如何在发生错误后终止程序,或者打印一个自定义的错误信息,并阻止程序进一步执行,我将不胜感激.

这是代码：

import java.util.Scanner;
 import java.util.GregorianCalendar;
 
 import javax.swing.JOptionPane;
 
 public class HeartRatesTest {
 
public static void main(String[] args) {
    HeartRates test= new HeartRates();
    Scanner input = new Scanner( System.in );
    GregorianCalendar gc = new GregorianCalendar();
    gc.setLenient(false);
 
        JOptionPane.showMessageDialog(null,"Welcome to the Heart Rate Calculator");;
        test.setFirstName(JOptionPane.showInputDialog("Please enter your first name: \n"));
        test.setLastName(JOptionPane.showInputDialog("Please enter your last name: \n"));
        JOptionPane.showMessageDialog(null,"Now enter your date of birth in Month/Day/Year order (hit enter after each): \n");
 
        try{
            String num1= JOptionPane.showInputDialog("Month: \n");
            int m= Integer.parseInt(num1);
            test.setMonth(m);
                gc.set(GregorianCalendar.MONTH,test.getMonth());
            num1= JOptionPane.showInputDialog("Day: \n");
            m= Integer.parseInt(num1);
            test.setDay(m);
                gc.set(GregorianCalendar.DATE,test.getDay());
            num1= JOptionPane.showInputDialog("Year: \n");
            m= Integer.parseInt(num1);
            test.setYear(m);
                gc.set(GregorianCalendar.YEAR,test.getYear());
 
                gc.getTime(); // exception thrown here
        }
 
        catch (Exception e) {
            e.printStackTrace();
            }   
 
 
 
    String message="Information for "+test.getFirstName()+" "+test.getLastName()+": \n\n"+"DOB: "+ test.getMonth()+"/" +test.getDay()+ "/" 
            +test.getYear()+ "\nAge: "+ test.getAge()+"\nMax Heart Rate: "+test.getMaxHR()+" BPM\nTarget Heart Rate(range): "+test.getTargetHRLow()
            +" - "+test.getTargetHRHigh()+" BPM";
    JOptionPane.showMessageDialog(null,message);
}

解决方法

不太确定为什么要在异常被捕获后终止应用程序 – 修正错误是不是更好？

在任何情况下,在你的catch块：

catch(Exception e) {
    e.printStackTrace(); //if you want it.
    //You could always just System.out.println("Exception occurred.");
    //Though the above is rather unspecific.
    System.exit(1);
}

java – 异常捕获但程序不断运行

解决方法

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