我刚刚开始使用
Java,作为第一个项目,我正在编写一个找到给定数字的根(在这种情况下为立方根)的程序.目前,我正在尝试牛顿拉尔夫森实现这一目标.这是代码 –
import java.util.Scanner;
import static java.lang.Math.abs;
public class newClass {
public static void main(String[] args) {
Scanner input = new Scanner(System.in);
System.out.println("Number whose cube root u wanna find:");
Double number = input.nextDouble();
Double epsilon = 0.0001;
Double ans = number/2.00;
while (abs((abs(number) - abs(Math.pow(ans,3))))>epsilon){
System.out.println("in loop");
ans = ans - ((Math.pow(ans,3) - number)/(3*Math.pow(ans,2)));
System.out.println(ans);
if ((number - ans)<=epsilon){
System.out.println(ans);
}
}
//System.out.println(Math.pow(number,1.0/3.0));
}
}
这只能达到11位数字,因为它对于IDE来说太大了.但是,如果我只是使用Math.pow(数字,1.0 / 3.0),它可以用于更大的数字,并且可以随时计算它.
那么,Math.pow()使用的算法是什么给出了即时答案？
我知道我的方法依赖于猜测,我猜math.pow()可能实际上是计算答案,但是如何？
解决方法
这是一个有趣的问题.如果您查看Java Math类的源代码,您会发现它调用StrictMath.pow(double1,double2),StrictMath的签名是public static native pow(double a,double b);
所以,最终,这是一个真正的本地电话,可能会因平台而有所不同.然而,在某个地方有一个实现,并不是很容易看.这里是函数的描述和函数本身的代码：
注意
看数学,试图理解它可能不可避免地会导致更多的问题.但是,通过在Java Math Function Source Code搜索这个Github并扫描数学概要,你可以更好地理解本机功能.快乐探索:)
方法说明
Method: Let x = 2 * (1+f)
1. Compute and return log2(x) in two pieces:
log2(x) = w1 + w2,where w1 has 53-24 = 29 bit trailing zeros.
2. Perform y*log2(x) = n+y' by simulating muti-precision
arithmetic,where |y'|<=0.5.
3. Return x**y = 2**n*exp(y'*log2)
特殊情况
1. (anything) ** 0 is 1
2. (anything) ** 1 is itself
3. (anything) ** NAN is NAN
4. NAN ** (anything except 0) is NAN
5. +-(|x| > 1) ** +INF is +INF
6. +-(|x| > 1) ** -INF is +0
7. +-(|x| < 1) ** +INF is +0
8. +-(|x| < 1) ** -INF is +INF
9. +-1 ** +-INF is NAN
10. +0 ** (+anything except 0,NAN) is +0
11. -0 ** (+anything except 0,NAN,odd integer) is +0
12. +0 ** (-anything except 0,NAN) is +INF
13. -0 ** (-anything except 0,odd integer) is +INF
14. -0 ** (odd integer) = -( +0 ** (odd integer) )
15. +INF ** (+anything except 0,NAN) is +INF
16. +INF ** (-anything except 0,NAN) is +0
17. -INF ** (anything) = -0 ** (-anything)
18. (-anything) ** (integer) is (-1)**(integer)*(+anything**integer)
19. (-anything except 0 and inf) ** (non-integer) is NAN
准确性
pow(x,y) returns x**y nearly rounded. In particular
pow(integer,integer)
always returns the correct integer provided it is
representable.
源代码
#ifdef __STDC__
double __ieee754_pow(double x,double y)
#else
double __ieee754_pow(x,y)
double x,y;
#endif
{
double z,ax,z_h,z_l,p_h,p_l;
double y1,t1,t2,r,s,t,u,v,w;
int i0,i1,i,j,k,yisint,n;
int hx,hy,ix,iy;
unsigned lx,ly;
i0 = ((*(int*)&one)>>29)^1; i1=1-i0;
hx = __HI(x); lx = __LO(x);
hy = __HI(y); ly = __LO(y);
ix = hx&0x7fffffff; iy = hy&0x7fffffff;
/* y==zero: x**0 = 1 */
if((iy|ly)==0) return one;
/* +-NaN return x+y */
if(ix > 0x7ff00000 || ((ix==0x7ff00000)&&(lx!=0)) ||
iy > 0x7ff00000 || ((iy==0x7ff00000)&&(ly!=0)))
return x+y;
/* determine if y is an odd int when x < 0
* yisint = 0 ... y is not an integer
* yisint = 1 ... y is an odd int
* yisint = 2 ... y is an even int
*/
yisint = 0;
if(hx<0) {
if(iy>=0x43400000) yisint = 2; /* even integer y */
else if(iy>=0x3ff00000) {
k = (iy>>20)-0x3ff; /* exponent */
if(k>20) {
j = ly>>(52-k);
if((j<<(52-k))==ly) yisint = 2-(j&1);
} else if(ly==0) {
j = iy>>(20-k);
if((j<<(20-k))==iy) yisint = 2-(j&1);
}
}
}
/* special value of y */
if(ly==0) {
if (iy==0x7ff00000) { /* y is +-inf */
if(((ix-0x3ff00000)|lx)==0)
return y - y; /* inf**+-1 is NaN */
else if (ix >= 0x3ff00000)/* (|x|>1)**+-inf = inf,0 */
return (hy>=0)? y: zero;
else /* (|x|<1)**-,+inf = inf,0 */
return (hy<0)?-y: zero;
}
if(iy==0x3ff00000) { /* y is +-1 */
if(hy<0) return one/x; else return x;
}
if(hy==0x40000000) return x*x; /* y is 2 */
if(hy==0x3fe00000) { /* y is 0.5 */
if(hx>=0) /* x >= +0 */
return sqrt(x);
}
}
ax = fabs(x);
/* special value of x */
if(lx==0) {
if(ix==0x7ff00000||ix==0||ix==0x3ff00000){
z = ax; /*x is +-0,+-inf,+-1*/
if(hy<0) z = one/z; /* z = (1/|x|) */
if(hx<0) {
if(((ix-0x3ff00000)|yisint)==0) {
z = (z-z)/(z-z); /* (-1)**non-int is NaN */
} else if(yisint==1)
z = -1.0*z; /* (x<0)**odd = -(|x|**odd) */
}
return z;
}
}
n = (hx>>31)+1;
/* (x<0)**(non-int) is NaN */
if((n|yisint)==0) return (x-x)/(x-x);
s = one; /* s (sign of result -ve**odd) = -1 else = 1 */
if((n|(yisint-1))==0) s = -one;/* (-ve)**(odd int) */
/* |y| is huge */
if(iy>0x41e00000) { /* if |y| > 2**31 */
if(iy>0x43f00000){ /* if |y| > 2**64,must o/uflow */
if(ix<=0x3fefffff) return (hy<0)? huge*huge:tiny*tiny;
if(ix>=0x3ff00000) return (hy>0)? huge*huge:tiny*tiny;
}
/* over/underflow if x is not close to one */
if(ix<0x3fefffff) return (hy<0)? s*huge*huge:s*tiny*tiny;
if(ix>0x3ff00000) return (hy>0)? s*huge*huge:s*tiny*tiny;
/* now |1-x| is tiny <= 2**-20,suffice to compute
log(x) by x-x^2/2+x^3/3-x^4/4 */
t = ax-one; /* t has 20 trailing zeros */
w = (t*t)*(0.5-t*(0.3333333333333333333333-t*0.25));
u = ivln2_h*t; /* ivln2_h has 21 sig. bits */
v = t*ivln2_l-w*ivln2;
t1 = u+v;
__LO(t1) = 0;
t2 = v-(t1-u);
} else {
double ss,s2,s_h,s_l,t_h,t_l;
n = 0;
/* take care subnormal number */
if(ix<0x00100000)
{ax *= two53; n -= 53; ix = __HI(ax); }
n += ((ix)>>20)-0x3ff;
j = ix&0x000fffff;
/* determine interval */
ix = j|0x3ff00000; /* normalize ix */
if(j<=0x3988E) k=0; /* |x|<sqrt(3/2) */
else if(j<0xBB67A) k=1; /* |x|<sqrt(3) */
else {k=0;n+=1;ix -= 0x00100000;}
__HI(ax) = ix;
/* compute ss = s_h+s_l = (x-1)/(x+1) or (x-1.5)/(x+1.5) */
u = ax-bp[k]; /* bp[0]=1.0,bp[1]=1.5 */
v = one/(ax+bp[k]);
ss = u*v;
s_h = ss;
__LO(s_h) = 0;
/* t_h=ax+bp[k] High */
t_h = zero;
__HI(t_h)=((ix>>1)|0x20000000)+0x00080000+(k<<18);
t_l = ax - (t_h-bp[k]);
s_l = v*((u-s_h*t_h)-s_h*t_l);
/* compute log(ax) */
s2 = ss*ss;
r = s2*s2*(L1+s2*(L2+s2*(L3+s2*(L4+s2*(L5+s2*L6)))));
r += s_l*(s_h+ss);
s2 = s_h*s_h;
t_h = 3.0+s2+r;
__LO(t_h) = 0;
t_l = r-((t_h-3.0)-s2);
/* u+v = ss*(1+...) */
u = s_h*t_h;
v = s_l*t_h+t_l*ss;
/* 2/(3log2)*(ss+...) */
p_h = u+v;
__LO(p_h) = 0;
p_l = v-(p_h-u);
z_h = cp_h*p_h; /* cp_h+cp_l = 2/(3*log2) */
z_l = cp_l*p_h+p_l*cp+dp_l[k];
/* log2(ax) = (ss+..)*2/(3*log2) = n + dp_h + z_h + z_l */
t = (double)n;
t1 = (((z_h+z_l)+dp_h[k])+t);
__LO(t1) = 0;
t2 = z_l-(((t1-t)-dp_h[k])-z_h);
}
/* split up y into y1+y2 and compute (y1+y2)*(t1+t2) */
y1 = y;
__LO(y1) = 0;
p_l = (y-y1)*t1+y*t2;
p_h = y1*t1;
z = p_l+p_h;
j = __HI(z);
i = __LO(z);
if (j>=0x40900000) { /* z >= 1024 */
if(((j-0x40900000)|i)!=0) /* if z > 1024 */
return s*huge*huge; /* overflow */
else {
if(p_l+ovt>z-p_h) return s*huge*huge; /* overflow */
}
} else if((j&0x7fffffff)>=0x4090cc00 ) { /* z <= -1075 */
if(((j-0xc090cc00)|i)!=0) /* z < -1075 */
return s*tiny*tiny; /* underflow */
else {
if(p_l<=z-p_h) return s*tiny*tiny; /* underflow */
}
}
/*
* compute 2**(p_h+p_l)
*/
i = j&0x7fffffff;
k = (i>>20)-0x3ff;
n = 0;
if(i>0x3fe00000) { /* if |z| > 0.5,set n = [z+0.5] */
n = j+(0x00100000>>(k+1));
k = ((n&0x7fffffff)>>20)-0x3ff; /* new k for n */
t = zero;
__HI(t) = (n&~(0x000fffff>>k));
n = ((n&0x000fffff)|0x00100000)>>(20-k);
if(j<0) n = -n;
p_h -= t;
}
t = p_l+p_h;
__LO(t) = 0;
u = t*lg2_h;
v = (p_l-(t-p_h))*lg2+t*lg2_l;
z = u+v;
w = v-(z-u);
t = z*z;
t1 = z - t*(P1+t*(P2+t*(P3+t*(P4+t*P5))));
r = (z*t1)/(t1-two)-(w+z*w);
z = one-(r-z);
j = __HI(z);
j += (n<<20);
if((j>>20)<=0) z = scalbn(z,n); /* subnormal output */
else __HI(z) += (n<<20);
return s*z;
}
