我已经遵循了
this tutorial来验证XML文件.但是在验证XML文件时收到异常.我做错了什么?我的代码:
XML模式:
XML模式:
<?xml version="1.0" encoding="utf-8" ?> <!-- definition of simple elements --> <xs:element name="first_name" type="xs:string" /> <xs:element name="last_name" type="xs:string" /> <xs:element name="phone" type="xs:string" /> <!-- definition of attributes --> <xs:attribute name="type" type="xs:string" use="required"/> <xs:attribute name="date" type="xs:date" use="required"/> <!-- definition of complex elements --> <xs:element name="reporter"> <xs:complexType> <xs:sequence> <xs:element ref="first_name" /> <xs:element ref="last_name" /> <xs:element ref="phone" /> </xs:sequence> </xs:complexType> </xs:element> <xs:element name="report"> <xs:complexType> <xs:attribute ref="type"/> <xs:attribute ref="date" /> <xs:sequence> <xs:element ref="reporter" /> </xs:sequence> </xs:complexType> </xs:element>
要验证的XML文件:
<?xml version="1.0" encoding="utf-8" ?> <report type="5" date="2012-12-14"> <reporter> <first_name>FirstName</firstname> <last_name>Lastname</lastname> <phone>+xxxxxxxxxxxx</phone> </reporter> </report>
用于验证的Java源代码
import javax.xml.XMLConstants; import javax.xml.transform.Source; import javax.xml.transform.stream.StreamSource; import javax.xml.validation.*; import org.xml.sax.SAXException; import java.io.*; public class ProtocolValidator { public static void main(String [] args) throws Exception { Source schemaFile = new StreamSource(new File("schema.xsd")); Source xmlFile = new StreamSource(new File("test_xml.xml")); SchemaFactory schemaFactory = SchemaFactory.newInstance(XMLConstants.W3C_XML_SCHEMA_NS_URI); Schema schema = schemaFactory.newSchema(schemaFile); Validator validator = schema.newValidator(); try{ validator.validate(xmlFile); System.out.println(xmlFile.getSystemId() + " is valid"); } catch (SAXException e) { System.out.println(xmlFile.getSystemId() + " is NOT valid"); System.out.println("Reason: " + e.getLocalizedMessage()); } } }
异常我正在收到:
Exception in thread "main" org.xml.sax.SAXParseException; systemId: file:/root/test/schema.xsd; lineNumber: 4; columnNumber: 50; The prefix "xs" for element "xs:element" is not bound. at com.sun.org.apache.xerces.internal.util.ErrorHandlerWrapper.createSAXParseException(ErrorHandlerWrapper.java:198)...
解决方法@H_301_19@
XML模式文件本身需要是一个有效的XML文档.您缺少外部架构元素和xs前缀的命名空间声明.
<xs:schema xmlns:xs="http://www.w3.org/2001/XMLSchema">
<!-- schema elements here -->
</xs:schema>
<xs:schema xmlns:xs="http://www.w3.org/2001/XMLSchema"> <!-- schema elements here --> </xs:schema>