所以我有一个UINavigationController,控制器A作为根控制器.
当我想要将控制器B推到顶部时,我想使用自定义的动画转换和自定义的交互式转换.这工作正常
当我想把控制器C放在顶部时,我想回到UINavigationController附带的默认push / pop转换.为了使这一切发生,我返回零
navigationController:animationControllerForOperation:fromViewController:toViewController:
然而,如果你返回零,那么
navigationController:interactionControllerForAnimationController:
将永远不会被调用,默认的“从左边缘的平移”弹出交互式转换不起作用.
有没有办法返回默认的push / pop动画控制器和交互控制器？
(是否具有id< UIViewControllerAnimatedTransitioning>和id< UIViewControllerInteractiveTransitioning>？)的具体实现)
还是其他一些方法？
解决方法
您应该将NavigationController的interactivePopGestureRecognizer委托设置为self,然后在-gestureRecognizerShouldBegin中处理其行为：
也就是说,当您想要内置的流行手势触发时,您必须从此方法返回YES.您的自定义手势也同样如此 – 您必须弄清楚您正在处理哪个识别器.
- (void)setup
{
self.interactiveGestureRecognizer = [[UIPanGestureRecognizer alloc] initWithTarget:self action:@selector(handleTransitionGesture:)];
self.interactiveGestureRecognizer.delegate = self;
[self.navigationController.view addGestureRecognizer:self.interactiveGestureRecognizer];
self.navigationController.interactivePopGestureRecognizer.delegate = self;
}
- (BOOL)gestureRecognizerShouldBegin:(UIGestureRecognizer *)gestureRecognizer
{
// Don't handle gestures if navigation controller is still animating a transition
if ([self.navigationController.transitionCoordinator isAnimated])
return NO;
if (self.navigationController.viewControllers.count < 2)
return NO;
UIViewController *fromVC = self.navigationController.viewControllers[self.navigationController.viewControllers.count-1];
UIViewController *toVC = self.navigationController.viewControllers[self.navigationController.viewControllers.count-2];
if ([fromVC isKindOfClass:[ViewControllerB class]] && [toVC isKindOfClass:[ViewControllerA class]])
{
if (gestureRecognizer == self.interactiveGestureRecognizer)
return YES;
}
else if (gestureRecognizer == self.navigationController.interactivePopGestureRecognizer)
{
return YES;
}
return NO;
}
您可以查看您的场景的sample project.视图控制器A和B之间的转换是自定义动画的,具有自定义的B-> A流行手势.视图控制器B和C之间的转换是默认的,内置导航控制器的弹出手势.
希望这可以帮助！
