如何在实例中访问静态协议方法 @H_502_2@我有一个Contact列表,该联系人可以是继承自Contact和GroupStatus协议的FamilyContact

@H_502_2@我想从GroupStatus调用静态方法但是徒劳无功……

@H_502_2@这是我的代码

protocol GroupStatus {
    static func isPrivate() -> Bool // static method that indicates the status
}

protocol IsBusy {
    func wizzIt()
}

class AdresseBook {

    private var contacts = [Contact]()

    func addOne(c: Contact) {
        contacts.append(c)
    }

    func listNonPrivated() -> [Contact]? {

        var nonPrivateContact = [Contact]()

        for contact in contacts {
            // here is I should call the static method provided by the protocol
            if self is GroupStatus {
                let isPrivate = contact.dynamicType.isPrivate()
                if !isPrivate {
                    nonPrivateContact.append(contact)
                }
            }
            nonPrivateContact.append(contact)
        }

        return nonPrivateContact
    }
}

class Contact : Printable {

    var name: String

    init(name: String) {
        self.name = name
    }

    func wizz() -> Bool {
        if let obj = self as? IsBusy {
            obj.wizzIt()
            return true
        }
        return false
    }

    var description: String {
        return self.name
    }
}

class FamilyContact: Contact,GroupStatus {

    static func isPrivate() -> Bool {
        return true
    }

}

@H_502_2@我无法编译Contact.Type没有名为’isPrivate’的成员

@H_502_2@我怎么称呼它？如果我删除静态关键字,它会起作用,但我认为将其定义为静态更合乎逻辑.

@H_502_2@如果我更换

let isPrivate = contact.dynamicType.isPrivate()

@H_502_2@通过

let isPrivate = FamilyContact.isPrivate()

@H_502_2@它工作,但我可以有超过1个子类

@H_502_2@如果我删除静态键盘,我可以这样做：

if let c = contact as? GroupStatus {
    if !c.isPrivate() {
        nonPrivateContact.append(contact)
    }
}

@H_502_2@但我想保留static关键字

if let gsType = contact.dynamicType as? GroupStatus.Type {
    if gsType.isPrivate() {
        // ...
    }
}

error: accessing members of protocol type value 'GroupStatus.Type' is unimplemented