我正在尝试使用UISearchController创建搜索功能.但是,我似乎无法使其与我的团队对象一起工作.我首先创建了一个包含id,name和shortname的Team Object.然后我从一个url中检索teamData,并将Team Objects添加到一个填充到tableView中的数组中.这个tableView包含一个searchController,它假设过滤数据,但没有任何反应.
阵列
var teamArray = Array<Team>() var filteredTableData = [String]()
GetTeams功能
func getTeams(url: String) {
isApiCalling = true
request(.GET,url,parameters: nil)
.response { (request,response,data,error) in
if error == nil {
let data: AnyObject = data!
let jsonArray = JSON(data: data as! NSData)
for (key: String,subJson: JSON) in jsonArray {
// Create an object and parse your JSON one by one to append it to your array
var newTeamObject = Team(id: subJson["id"].intValue,name: subJson["name"].stringValue,shortname: subJson["shortname"].stringValue)
self.teamArray.append(newTeamObject)
}
self.isApiCalling = false
self.tableView.reloadData()
self.refreshControl?.endRefreshing()
}
}
}
的cellForRowAtIndexPath
override func tableView(tableView: UITableView,cellForRowAtIndexPath indexPath: NSIndexPath) -> UITableViewCell {
let cell = tableView.dequeueReusableCellWithIdentifier("teamCell",forIndexPath: indexPath) as! TeamCell
cell.textLabel?.font = UIFont(name: "HelveticaNeue-Light",size: 20)
cell.textLabel?.text = self.teamArray[indexPath.row].name as String
if (self.cellSelected.containsObject(indexPath)) {
cell.accessoryView = cell.accessoryCheck
} else {
cell.accessoryView = cell.accessoryUncheck
}
return cell
}
筛选数据
func updateSearchResultsForSearchController(searchController: UISearchController)
{
filteredTableData.removeAll(keepCapacity: false)
let searchPredicate = NSPredicate(format: "SELF CONTAINS[c] %@",searchController.searchBar.text)
let array = (teamArray as NSArray).filteredArrayUsingPredicate(searchPredicate)
filteredTableData = array as! [String]
self.tableView.reloadData()
}
团队对象
class Team{
var id: Int!
var name: NSString!
var shortname: NSString!
init(id: Int,name:NSString,shortname: NSString) {
self.id = id
self.name = name
self.shortname = shortname
}
}
解决方法
teamArray中的对象没有SELF属性.您不能使用SELF一次搜索对象的所有属性.您必须提供属性的名称,如果要搜索多个属性,则必须将所有这些属性添加到谓词中.
let searchPredicate = NSPredicate(format: "name CONTAINS[c] %@",searchController.searchBar.text)
如果您需要更多属性,请执行以下操作：
let searchPredicate = NSPredicate(format: "name CONTAINS[c] %@ OR shortname CONTAINS[c] %@",searchController.searchBar.text,searchController.searchBar.text)
