从webservice(API)解码
JSON时,我收到错误:
Could not cast value of type '__NSDictionaryM' (0x1037ad8a8) to 'NSArray' (0x1037ad470).
我的代码:
var kGetURL = "http://bitnami.local/cscart_demo/api/users" //var kGetURL = "http://localhost/fendy/getjson.PHP" var json : Array<AnyObject> = [] override func viewDidLoad() { super.viewDidLoad() start() } func getData(data : NSData){ //error at this line : json = NSJSONSerialization.JSONObjectWithData(data,options: NSJSONReadingOptions.MutableContainers,error: nil) as! Array<AnyObject> //error tableView.reloadData() } func start(){ var url : NSURL = NSURL(string: kGetURL)! var data : NSData = NSData(contentsOfURL: url)! getData(data) }
如果我将url更改为http://localhost/fendy/getjson.php,它的工作非常好.
如果我的网址是http://bitnami.local/cscart_demo/api/users,我会收到错误
来自webservice http://localhost/fendy/getjson.php的回复:
[{"id":"17","Name":"KFC","Message":"awesome"},{"id":"18","Name":"McDonald","Message":"good"},{"id":"23","Name":"Burger King","Message":"tasty"},{"id":"38","Name":"Pizza hut","Message":"yummy"},{"id":"39","Name":"Steak","Message":"very DelicIoUs"}]
来自webservice http://bitnami.local/cscart_demo/api/users的回复:
{"users": [{"user_id":"4","user_login":"user_4","is_root":"N","timestamp":"1441608048","user_type":"C","status":"A","firstname":"","lastname":"","email":"fendy.w@mvig.net","company":"","company_id":"1","company_name":"Simtech"},{"user_id":"3","user_login":"customer","timestamp":"1441604240","firstname":"Customer","lastname":"Customer","email":"customer@example.com","company":"Simtech",{"user_id":"1","user_login":"admin","is_root":"Y","user_type":"A","firstname":"John","lastname":"Doe","email":"robby@mvig.net","company":"Your company","company_id":"0","company_name":null}],"params":{"page":1,"items_per_page":"10","sort_order":"asc","sort_by":"name","sort_order_rev":"desc","total_items":"3"}}
我认为它的风格是相同的,但为什么不使用网址http://bitnami.local/cscart_demo/api/users.谁有人可以帮忙?
解决方法
bitnami响应以{开头,因此它是
JSON object,对应于NSDictionary.另一个以[表示数组开头]开头.
您需要将json的类型更改为Dictionary< String,AnyObject>,然后反序列化,如下所示:
json = NSJSONSerialization.JSONObjectWithData(data,error: nil) as! Dictionary<String,AnyObject>