我正在努力了解NSOperationQueue,并尝试创建最简单的例子.我有以下几点：
NSOperationQueue *myOQ=[[NSOperationQueue alloc] init];
[myOQ addOperationWithBlock:^(void){
NSLog(@"here is something for jt 2");
}];
[myOQ addOperationWithBlock:^(void){
NSLog(@"oh is this going to work 2");
}];
但是想这样做：
void (^jt)() = ^void(){
NSLog(@"here is something for jt");
};
void (^cl)() = ^void(){
NSLog(@"oh is this going to work");
};
NSOperationQueue *myOQ=[[NSOperationQueue alloc] init];
[myOQ addOperation:jt];
[myOQ addOperation:cl];
这可能是后者吗？可以将块转换为NSOperation吗？
提前
@H_502_12@解决方法
你可以：
NSBlockOperation *jtOperation = [NSBlockOperation blockOperationWithBlock:^{
NSLog(@"here is something for jt");
}];
NSBlockOperation *clOperation = [NSBlockOperation blockOperationWithBlock:^{
NSLog(@"oh is this going to work");
}];
[myOQ addOperation:jtOperation];
[myOQ addOperation:clOperation];
话虽如此,我通常会添加操作,除非我真的需要NSOperation对象指针的其他原因(例如,建立操作之间的依赖关系等).
@H_502_12@ @H_502_12@