在创建一个这样的结构：
type Foo struct {
name string
}
func (f Foo) SetName(name string){
f.name=name
}
func (f Foo) GetName string (){
return f.name
}
p:=new(Foo)
p.SetName("Abc")
name:=p.GetName()
fmt.Println(name)
评论(和工作)示例：
package main
import "fmt"
type Foo struct {
name string
}
// SetName receives a pointer to Foo so it can modify it.
func (f *Foo) SetName(name string) {
f.name = name
}
// Name receives a copy of Foo since it doesn't need to modify it.
func (f Foo) Name() string {
return f.name
}
func main() {
// Notice the Foo{}. The new(Foo) was just a syntactic sugar for &Foo{}
// and we don't need a pointer to the Foo,so I replaced it.
// Not relevant to the problem,though.
p := Foo{}
p.SetName("Abc")
name := p.Name()
fmt.Println(name)
}
Test it并采取A Tour of Go以了解更多关于方法和指针，以及Go的基本知识。
