http://play.golang.org/p/ZsALO8oF3W
我想要遍历一个字符串并返回字符值。如何，不返回每个字母的数值，并返回实际的字符？
现在我得到这个
0 72 72 1 101 101 2 108 108 3 108 108 4 111 111
我想要的输出是
0 h h
1 e e
2 l l
3 l l
4 o o
package main
import "fmt"
func main() {
str := "Hello"
for i,elem := range str {
fmt.Println(i,str[i],elem)
}
for elem := range str {
fmt.Println(elem)
}
}
谢谢，
@H_301_17@
原文链接：https://www.f2er.com/go/187056.html07000
For a string value,the “range” clause iterates over the Unicode code
points in the string starting at byte index 0. On successive
iterations,the index value will be the index of the first byte of
successive UTF-8-encoded code points in the string,and the second
value,of type rune,will be the value of the corresponding code
point. If the iteration encounters an invalid UTF-8 sequence,the
second value will be 0xFFFD,the Unicode replacement character,and
the next iteration will advance a single byte in the string.
例如，
package main
import "fmt"
func main() {
str := "Hello"
for _,r := range str {
c := string(r)
fmt.Println(c)
}
fmt.Println()
for i,r := range str {
fmt.Println(i,r,string(r))
}
}
输出：
H e l l o 0 72 H 1 101 e 2 108 l 3 108 l 4 111 o
