有没有办法在Golang中将XML([] byte)转换为JSON输出？
我有以下函数,其中body是[] byte但我想在一些操作之后将这个XML响应转换为JSON.我在xml包中尝试过Unmarshal但没有成功：
// POST
func (u *UserResource) authenticateUser(request *restful.Request,response *restful.Response) {
App := new(Api)
App.url = "http://api.com/api"
usr := new(User)
err := request.ReadEntity(usr)
if err != nil {
response.AddHeader("Content-Type","application/json")
response.WriteErrorString(http.StatusInternalServerError,err.Error())
return
}
buf := []byte("<app version=\"1.0\"><request>1111</request></app>")
r,err := http.Post(App.url,"text/plain",bytes.NewBuffer(buf))
if err != nil {
response.AddHeader("Content-Type",err.Error())
return
}
defer r.Body.Close()
body,err := IoUtil.ReadAll(r.Body)
response.AddHeader("Content-Type","application/json")
response.WriteHeader(http.StatusCreated)
// err = xml.Unmarshal(body,&usr)
// if err != nil {
// fmt.Printf("error: %v",err)
// return
// }
response.Write(body)
// fmt.Print(&usr.userName)
}
我也在使用Go-restful包
如果需要将XML文档转换为具有未知结构的JSON,则可以使用
goxml2json.
示例：
import (
// Other imports ...
xj "github.com/basgys/goxml2json"
)
func (u *UserResource) authenticateUser(request *restful.Request,response *restful.Response) {
// Extract data from restful.Request
xml := strings.NewReader(`<?xml version="1.0" encoding="UTF-8"?><app version="1.0"><request>1111</request></app>`)
// Convert
json,err := xj.Convert(xml)
if err != nil {
// Oops...
}
// ... Use JSON ...
}
Note : I’m the author of this library.
