package main

import (
    "encoding/json"
    "encoding/xml"
    "fmt"
)

type Persons struct {
    Person []struct {
        Name string
        Age  int
    }
}
type Places struct {
    Place []struct {
        Name    string
        Country string
    }
}

type Parks struct {
    Park struct {
        Name     []string
        Capacity []int
    }
}

const personXml = `
    <Persons>
        <Person><Name>Koti</Name><Age>30</Age></Person>
        <Person><Name>Kanna</Name><Age>29</Age></Person>
    </Persons>
`

const placeXml = `
    <Places>
        <Place><Name>Chennai</Name><Country>India</Country></Place>
        <Place><Name>London</Name><Country>UK</Country></Place>
    </Places>
`

const parkXml = `
    <Parks>
        <Park><Name>National Park</Name><Capacity>10000</Capacity></Park>
        <Park>Asian Park</Name><Capacity>20000</Capacity></Park>
    </Parks>
`

func WhatIamUsing() {
    var persons Persons
    xml.Unmarshal([]byte(personXml),&persons)
    per,_ := json.Marshal(persons)
    fmt.Printf("%s\n",per)

    var places Places
    xml.Unmarshal([]byte(placeXml),&places)
    pla,_ := json.Marshal(places)
    fmt.Printf("%s\n",pla)

    var parks Parks
    xml.Unmarshal([]byte(parkXml),&parks)
    par,_ := json.Marshal(parks)
    fmt.Printf("%s\n",par)
}

我想要的是一个通用函数,它采用xml字符串和dataStruct
并返回Json输出.但是下面的函数会抛出一个错误
怎么称赞这个？

func Xml2Json(xmlString string,DataStruct interface{}) (jsobj string,err error) {
    var dataStruct DataStruct
    xml.Unmarshal([]byte(personXml),&dataStruct)
    js,_ := json.Marshal(dataStruct)
    return fmt.Sprintf("%s\n",js),nil
}

func main() {
    jsonstring,_ := Xml2Json(personXml,Persons)
}

错误信息：

prog.go：73：DataStruct不是一个类型

prog.go：80：type Persons不是表达式

goplay链接：http://play.golang.org/p/vayb0bawKx

func Xml2Json(xmlString string,value interface{}) (string,error) {
    if err := xml.Unmarshal([]byte(xmlString),value); err != nil {
        return "",err
    }
    js,err := json.Marshal(value)
    if err != nil {
        return "",err
    }
    return string(js),nil
}

var persons Persons
Xml2Json(personXML,&persons)