我正在研究一些医疗软件,我需要根据以下规则以非常具体的方式输出所有年龄段：
If under 6 Weeks old : ###D (Number of Days) If under 6 Months old : ###W (Number of Weeks) If under 2 Years old : ###M (Number of Months) If above 2 Years old : ###Y (Number of Years)
使用C#我试图找到一个简单的方法,只使用一个人的出生日期,任何帮助将不胜感激.
解决方法
我昨天正在做类似的事情,但这样的事情应该适合你的需要:(假设7天,31天,365天等)
修订方法:(根据鲍勃的建议修正)
public static string ConvertAge(DateTime dob)
{
DateTime today = DateTime.Today;
string fmt = "{0:0##}{1}";
//Greater than 2 Years old - Ouput Years
if (dob <= today.AddYears(-2))
return string.Format(fmt,(dob.DayOfYear <= today.DayOfYear) ?
(today.Year - dob.Year) : (today.Year - dob.Year)-1,"Y");
//Less than 2 Years - Output Months
if (dob < today.AddMonths(-2))
return string.Format(fmt,(dob.DayOfYear <= today.DayOfYear) ?
(today.Year - dob.Year) * 12 + (today.Month - dob.Month) :
((today.Year - dob.Year) * 12 + (today.Month - dob.Month))-1,"M");
//Less than 2 Months - Output Weeks
if (dob < today.AddDays(-2 * 7))
return string.Format(fmt,(today - dob).Days / 7,"W");
//Less than 2 Weeks - Output Days
return string.Format(fmt,(today - dob).Days,"D");
}
上一种方法：
public string ConvertAge(DateTime dateOfBirth)
{
int daysOld = (DateTime.Now - dateOfBirth).Days;
//Age < 6 Weeks
if (daysOld < (6 * 7))
return String.Format("{0:0##}{1}",daysOld,'D');
//Age < 6 Months
else if (daysOld < (6 * 31))
return String.Format("{0:0##}{1}",daysOld/7,'W');
//Age < 2 Years
else if (daysOld < (2 * 365))
return String.Format("{0:0##}{1}",daysOld / 31,'M');
//Age >= 2 Years
else
return String.Format("{0:0##}{1}",daysOld / 365,'Y');
}
希望这可以帮助！
