c# – 在Console App中反序列化Json

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我正在创建一个Web API端点,它将作为一种服务来检索我们的应用程序配置,执行日志记录等.我遇到的问题是能够在控制台应用程序中反序列化Json.

建立

public class Person
{
    public string FirstName { get; set; }
    public string LastName { get; set; }
    public DateTime DateOfBirth { get; set; }
}

Web API

[HttpGet]
[Route("Person")]
public IHttpActionResult GetPerson()
{
    Person person = new Person
    {
        FirstName = "Steve",LastName = "Rogers",DateOfBirth = new DateTime(1920,7,4)
    };

    return Ok(JsonConvert.SerializeObject(person));
}

控制台应用

using (var client = new HttpClient())
{
    client.BaseAddress = new Uri("http://localhost");

    var response = client.GetAsync("api/Person").Result;
    var data = response.Content.ReadAsStringAsync().Result;
    var person = DeserializeJson<Person>(data);
}

public static T DeserializeJson<T>(string input)
{
    var result = JsonConvert.DeserializeObject(input);
    var result2 = JsonConvert.DeserializeObject(result.ToString());
    return JsonConvert.DeserializeObject<T>(result2.ToString());
}

data = “\”{\\”FirstName\\”:\\”Steve\\”,\\”LastName\\”:\\”Rogers\\”,\\”DateOfBirth\\”:\\”1920-07-04T00:00:00\\”}\””

result = “{\”FirstName\”:\”Steve\”,\”LastName\”:\”Rogers\”,\”DateOfBirth\”:\”1920-07-04T00:00:00\”}”

result2 = {{
“FirstName”: “Steve”,
“LastName”: “Rogers”,
“DateOfBirth”: “1920-07-04T00:00:00”
}}

我遇到的问题是,在第3次反序列化之前,我无法反序列化为Person对象. result2中的值是我能够成功反序列化为Person的唯一值.有没有更有效的方法来完成这种反序列化?优选地,没有3次迭代.

解决方法

我能够成功运行以下内容(基于 this Microsoft article):

控制台应用:

static void Main(string[] args)
    {
        RunAsync().Wait();
    }

    static async Task RunAsync()
    {
        using (var client = new HttpClient())
        {
            client.BaseAddress = new Uri("http://localhost:3963/");
            client.DefaultRequestHeaders.Accept.Clear();
            client.DefaultRequestHeaders.Accept.Add(new MediaTypeWithQualityHeaderValue("application/json"));

            HttpResponseMessage response = await client.GetAsync("api/Person");
            Person product = await response.Content.ReadAsAsync<Person>();
        }
    }

控制器:

public class PersonController : ApiController
{
    public Person GetPerson()
    {
        Person person = new Person
        {
            FirstName = "Steve",4)
        };
        return person;
    }
}

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