我有一个
XMLDocument,我需要读入并转换为一组对象.我有以下物品
public class Location
{
public string Name;
public List<Building> Buildings;
}
public class Building
{
public string Name;
public List<Room> Rooms;
}
我有以下XML文件：
<?xml version="1.0" encoding="utf-8" ?>
<info>
<locations>
<location name="New York">
<Building name="Building1">
<Rooms>
<Room name="Room1">
<Capacity>18</Capacity>
</Room>
<Room name="Room2">
<Capacity>6</Capacity>
</Room>
</Rooms>
</Building>
<Building name="Building2">
<Rooms>
<Room name="RoomA">
<Capacity>18</Capacity>
</Room>
</Rooms>
</Building>
</location>
<location name ="London">
<Building name="Building45">
<Rooms>
<Room name="Room5">
<Capacity>6</Capacity>
</Room>
</Building>
</location>
</locations>
</info>
这样做的最佳方式是什么？我应该自动将xmldocument序列化到对象还是我需要解析每个元素并手动转换为我的对象？特别是,我试图弄清楚如何转换集合(位置,建筑物等).
将此XML文件转换为基本的最佳建议是什么？
List<Location>
对象？
解决方法
您可以从修复XML开始,因为在您显示的示例中,您有未闭合的标记.你也可以包装< Building>标签到< Buildings>集合,以便能够在此Location类别中具有除建筑物之外的其他属性.
<?xml version="1.0" encoding="utf-8" ?>
<info>
<locations>
<location name="New York">
<Buildings>
<Building name="Building1">
<Rooms>
<Room name="Room1">
<Capacity>18</Capacity>
</Room>
<Room name="Room2">
<Capacity>6</Capacity>
</Room>
</Rooms>
</Building>
<Building name="Building2">
<Rooms>
<Room name="RoomA">
<Capacity>18</Capacity>
</Room>
</Rooms>
</Building>
</Buildings>
</location>
<location name="London">
<Buildings>
<Building name="Building45">
<Rooms>
<Room name="Room5">
<Capacity>6</Capacity>
</Room>
</Rooms>
</Building>
</Buildings>
</location>
</locations>
</info>
修复XML后,您可以调整模型.我建议您使用属性而不是类中的字段：
public class Location
{
[XmlAttribute("name")]
public string Name { get; set; }
public List<Building> Buildings { get; set; }
}
public class Building
{
[XmlAttribute("name")]
public string Name { get; set; }
public List<Room> Rooms { get; set; }
}
public class Room
{
[XmlAttribute("name")]
public string Name { get; set; }
public int Capacity { get; set; }
}
[XmlRoot("info")]
public class Info
{
[XmlArray("locations")]
[XmlArrayItem("location")]
public List<Location> Locations { get; set; }
}
现在剩下的就是反序列化XML：
var serializer = new XmlSerializer(typeof(Info));
using (var reader = XmlReader.Create("locations.xml"))
{
Info info = (Info)serializer.Deserialize(reader);
List<Location> locations = info.Locations;
// do whatever you wanted to do with those locations
}
