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What’s the best way to ensure a base class’s static constructor is called?6个
可以说我有两节课：
可以说我有两节课：
public abstract class Foo
{
static Foo()
{
print("4");
}
}
public class Bar : Foo
{
static Bar()
{
print("2");
}
static void DoSomething()
{
/*...*/
}
}
我预计在调用Bar.DoSomething()之后(假设这是我第一次访问Bar类),事件的顺序将是：
> Foo的静态构造函数(再次,假设首次访问)>打印4
> Bar的静态构造函数>打印2
>执行DoSomething
在底线我预计会打印42张.
经过测试,似乎只有2个正在打印.
And that is not even an answer.
你能解释一下这种行为吗？
解决方法
规范说明：
The static constructor for a class executes at most once in a given application domain. The execution of a static constructor is triggered by the first of the following events to occur within an application domain:
- An instance of the class is created.
- Any of the static members of the class are referenced.
因为您没有引用基类的任何成员,所以构造函数不会被驱逐.
试试这个：
public abstract class Foo
{
static Foo()
{
Console.Write("4");
}
protected internal static void Baz()
{
// I don't do anything but am called in inherited classes'
// constructors to call the Foo constructor
}
}
public class Bar : Foo
{
static Bar()
{
Foo.Baz();
Console.Write("2");
}
public static void DoSomething()
{
/*...*/
}
}
欲获得更多信息：
> C# in Depth – Jon Skeet: C# and beforefieldinit
> StackOverflow: What’s the best way to ensure a base class’s static constructor is called?
