如何让microsoft unity为给定的接口类型“构造”一个类的列表.
非常简单的例子：
List<IShippingCalculation> list = new List<IShippingCalculation>();
list.Add(new NewYorkShippingCalculation());
list.Add(new FloridaShippingCalculation());
list.Add(new AlaskShippingCalculation());
//Not What I want
public void calcship(List<IShippingCalculation> list)
{
var info = new ShippingInfo(list);
info.CalculateShippingAmount(State.Alaska)
}
//Somehow in unity,must i do this for all the concrete classes?
//how does it know to give a list.
Container.RegisterType<IShippingInfo,new AlaskaShippingCalculation()>();??
//What I want
public void calcship(IShippingInfo info)
{
info.CalculateShippingAmount(State.Alaska)
}
谢谢！
解决方法
如果您使用的是Unity 2,则可以使用ResolveAll< T>
Container.RegisterType<IShippingInfo,FloridaShippingCalculation>("Florida");
Container.RegisterType<IShippingInfo,NewYorkShippingCalculation>("NewYork");
Container.RegisterType<IShippingInfo,AlaskaShippingCalculation>("Alaska");
IEnumerable<IShippingInfo> infos = Container.ResolveAll<IShippingInfo>();
