C#为class和operator =分配默认属性

问题1：

我有一个简单的winforms应用程序,我希望DataBind我的Person.Name属性到一个文本框.名称的类型为StringField.我最初将Name属性定义为String.数据绑定在值类型(如String)上非常有用.我希望StringField.Value属性是StringField的默认属性.我想在textBox中看到StringField.Value的值而不是文本“FieldApp.StringField”.

问题2：

我希望能够使用operator =将字符串分配给StringField.此赋值将导致设置StringField.Value成员.

这可以实现吗？

using System;
using System.Collections.Generic;
using System.ComponentModel;
using System.Data;
using System.Drawing;
using System.Linq;
using System.Text;
using System.Windows.Forms;

namespace FieldApp
{
    public class StringField
    {
        public string Value { get; set; }    
    }

    public class Person
    {

        //private String _Name;
        //public String Name
        //{
        //    get { return _Name; }
        //    set { _Name = value; }
        //}

        //public Person(string name)
        //{
        //    Name = name;
        //}

        private StringField _Name;
        public StringField Name
        {
            get { return _Name; }
            set { _Name = value; }
        }

        public Person(string name)
        {
            Name = new StringField();
            Name.Value = name;
        }
    }

    public partial class FieldAppForm : Form
    {
        Person person = new Person("steve");

        public FieldAppForm()
        {
            InitializeComponent();
        }

        private void button1_Click(object sender,EventArgs e)
        {
            //our form contains a button1 and textBox1

            //this compiles
            person.Name.Value = "steve";

            //this does not. Is there anyway to accomplish this?
            person.Name = "steve";

            //steve appears in the textBox 
            textBox1.DataBindings.Add("Text",person,"Name.Value");

            //FieldApp.StringField appears in the textBox 
            textBox1.DataBindings.Add("Text","Name");
        }
    }
}

解决方法

您可以创建一个implisit运算符重载.然后你可以从这样的字符串创建Stringfield：

StringField field = "value of new object";
string value=(string)field;

知道这会创建一个新的StringField对象.我不会建议你这样做.

[System.Diagnostics.DebuggerDisplay("{Value}")]
public class StringField
{
    public string Value { get; set; }
    public static implicit operator StringField(string s)
    {
        return new StringField { Value = s };
    }

    public static explicit operator string(StringField f)
    {
        return f.Value;
    }
    public override string ToString()
    {
        return Value;
    }
}

原文链接：https://www.f2er.com/csharp/95066.html

C#为class和operator =分配默认属性

解决方法

猜你在找的C#相关文章