让我说我有物品
items : [{id:1,...},{id:2,{id:3,...}]
并订购：[2,3,1]得到一个可枚举
items : [{id:2,{id:1,...}]
我期望它是一个东西
items.Select(o => new {key = ordering[i++],value = o})
.OrderBy(k => k.key)
.Select(o => o.value)
但是有没有更清洁的解决方案？
以下我已经验证了这项工作(HimBromBeere,Domysee,qxg)
var expectedOrder = ordering.Select(x => result.First(o => o.Id == x));
var expectedOrder = result.OrderBy(item => Array.FindIndex(ordering,i => i == item.Id));
var expectedOrder = result.OrderBy(item => ordering.ToList().FindIndex(i => i == item.Id));
var expectedOrder =
from o in ordering
join i in result
on o equals i.Id
select i;
Fwi,这是验证测试：
[Test]
[TestCase(1,2,3)]
[TestCase(1,2)]
[TestCase(2,1,3)]
[TestCase(2,1)]
[TestCase(3,2)]
public void Test_Should_Fail_If_GetMessages_Does_Not_Return_Sorted_By_Sent_Then_By_Id_Result(params int[] ordering)
{
var questions = GetQuestionsData();
Mock.Get(_questionService)
.Setup(o => o.GetQuestions())
.Returns(questions);
var result = _mailBoxService.GetMessages();
var expectedOrder = ordering.Select(x => result.First(o => o.Id == x));
// Act
Action sortOrder = () => expectedOrder.Should()
.BeInDescendingOrder(o => o.Sent)
.And.BeInDescendingOrder(o => o.Id);
// Assert
sortOrder.ShouldThrow<AssertionException>();
}
解决方法
这样的事我猜：
var result = ordering.Select(x => items.First(y => y.id == x.id));
工作实例：
var items = new[] { new { id = 1,name = "1" },new { id = 2,name = "2" },new { id = 3,name = "3" },new { id = 4,name = "4" } };
var result = new[] { 2,1 }.Select(x => items.First(y => y.id == x));
这也会排除这些项目,其索引不包含在排序中.
