如何创建排除最低温度并计算平均温度的方法.我只想要一个提示,而不是完整的解决方案,因为我想自己解决我的编程问题.我只有大约10个班级…评论人们的评论我的教授没有讲课,我读过我的书多次回顾过它.
我让这个程序从用户那里拿一个号码.该数字将添加到数组中.该数组用于创建类Temp的实例以打印最低和最高临时值.
class Program
{
static void Main(string[] args)
{
Console.Write("Enter a Temperature in Degrees:");
string n = Console.ReadLine();
int number = Convert.ToInt32( n);
Temp t = new Temp(100,52,98,30,11,54,number);
Console.WriteLine("Lowest Temperature:{0}",t.lowest());
Console.WriteLine("Highest Temperature: {0}",t.highest());
Console.WriteLine("Average Temperature: {0}",t.Average());
}
public class Temp
{
private int[] temp = new int[7]; // array
public Temp(int d1,int d2,int d3,int d4,int d5,int d6,int d7) // constructor with 7 parameters
{
temp[0] = d1; // assigning constructor parameters to array
temp[1] = d2;
temp[2] = d3;
temp[3] = d4;
temp[4] = d5;
temp[5] = d6;
temp[6] = d7;
}
public int lowest() // returning the lowest value of the set of numbers
{
int smallest = 150;
for (int c = 0; c < 7; c++)
{
if (temp[c] < smallest)
{
smallest = temp[c];
}
}
return smallest;
}
public int highest()
{
int highest = -1;
for (int c = 0; c < 7; c++)
{
if (temp[c] > highest)
{
highest = temp[c];
}
}
return highest;
}
public double Average()
{
double average = 0;
for (int c = 0; c < 7; c++)
{
}
return average;
}
}
}
解决方法
使用单个循环非常容易：
public double Average()
{
// Initialize smallest with the first value.
// The loop will find the *real* smallest value.
int smallest = temp[0];
// To calculate the average,we need to find the sum of all our temperatures,// except the smallest.
int sum = temp[0];
// The loop does two things:
// 1. Adds all of the values.
// 2. Determines the smallest value.
for (int c = 1; c < temp.Length; ++c)
{
if (temp[c] < smallest)
{
smallest = temp[c];
}
sum += temp[c];
}
// The computed sum includes all of the values.
// Subtract the smallest.
sum -= smallest;
double avg = 0;
// and divide by (Length - 1)
// The check here makes sure that we don't divide by 0!
if (temp.Length > 1)
{
avg = (double)sum/(temp.Length-1);
}
return avg;
}
