早上好家伙
有没有一种在C#中使用正则表达式的好方法,以便在字符串变量中查找所有文件名及其路径？
例如,如果您有此字符串：
string s = @"Hello John these are the files you have to send us today: <file>C:\Development\Projects 2010\Accounting\file20101130.csv</file>,<file>C:\Development\Projects 2010\Accounting\orders20101130.docx</file> also we would like you to send <file>C:\Development\Projects 2010\Accounting\customersupdated.xls</file> thank you";
结果将是：
C:\Development\Projects 2010\Accounting\file20101130.csv C:\Development\Projects 2010\Accounting\orders20101130.docx C:\Development\Projects 2010\Accounting\customersupdated.xls
解决方法
这是我想出来的：
using System;
using System.Text.RegularExpressions;
public class Test
{
public static void Main()
{
string s = @"Hello John these are the files you have to send us today:
C:\projects\orders20101130.docx also we would like you to send
C:\some\file.txt,C:\someother.file and d:\some file\with spaces.ext
Thank you";
Extract(s);
}
private static readonly Regex rx = new Regex
(@"[a-z]:\\(?:[^\\:]+\\)*((?:[^:\\]+)\.\w+)",RegexOptions.IgnoreCase);
static void Extract(string text)
{
MatchCollection matches = rx.Matches(text);
foreach (Match match in matches)
{
Console.WriteLine("'{0}'",match.Value);
}
}
}
产品:(见ideone)
'C:\projects\orders20101130.docx',file: 'orders20101130.docx' 'C:\some\file.txt',file: 'file.txt' 'C:\someother.file',file: 'someother.file' 'd:\some file\with spaces.ext',file: 'with spaces.ext'
正则表达式不是非常强大(它确实做了一些假设)但它也适用于您的示例.
如果您使用< file>,这是该程序的一个版本标签.将正则表达式和Extract更改为：
private static readonly Regex rx = new Regex
(@"<file>(.+?)</file>",RegexOptions.IgnoreCase);
static void Extract(string text)
{
MatchCollection matches = rx.Matches(text);
foreach (Match match in matches)
{
Console.WriteLine("'{0}'",match.Groups[1]);
}
}
也可在ideone上获得.
