我试图解析调用rest API时得到的json响应.
我面临的问题是反序列化每次都不起作用,即使我发出相同的请求.我不知道如何修复它,因为try.catch没有做任何更好的事情.
我面临的问题是反序列化每次都不起作用,即使我发出相同的请求.我不知道如何修复它,因为try.catch没有做任何更好的事情.
此外,当我试图解析一个非常大的响应(20个json对象)时,程序永远不会工作.
Unterminated string. Expected delimiter: “. Path ‘drinks[0].strMeasure4’,line 3,position 720.
是我得到的错误之一,它永远不会是一样的.
using Newtonsoft.Json;
using System;
using System.Collections.Generic;
using System.Linq;
using System.Net.Sockets;
using System.Text;
using System.Threading.Tasks;
using ConsoleApplication1;
namespace TCPclient
{
class Program
{
static void Main(string[] args)
{
TcpClient client = new TcpClient();
client.Connect("www.thecocktaildb.com",80); // geen http
string request = getRequestCoctail("margarita");
NetworkStream stream = client.GetStream();
byte[] buffer = Encoding.Default.GetBytes(request);
stream.Write(buffer,buffer.Length);
StringBuilder message = new StringBuilder();
int numberOfBytesRead = 0;
byte[] receiveBuffer = new byte[1024];
do
{
numberOfBytesRead = stream.Read(receiveBuffer,receiveBuffer.Length);
message.AppendFormat("{0}",Encoding.ASCII.GetString(receiveBuffer,numberOfBytesRead));
} while (stream.DataAvailable);
string response = message.ToString();
//Console.WriteLine("Response: \n" + response);
response = response.Substring(response.IndexOf("\r\n\r\n"));
try
{
dynamic jsonData = JsonConvert.DeserializeObject(response);
List<Drink> drankjes = new List<Drink>();
for (int i = 0; i < jsonData.drinks.Count; i++)
{
try
{
string id = jsonData.drinks[i].idDrink;
string drink = jsonData.drinks[i].strDrink;
string category = jsonData.drinks[i].strCategory;
string instructions = jsonData.drinks[i].strInstructions;
string glass = jsonData.drinks[i].strGlass;
Console.WriteLine(glass);
var d = new Drink(id,drink,category,instructions);
drankjes.Add(d);
}
catch (Exception)
{
Console.WriteLine("error");
}
}
}
catch (Exception e)
{
Console.WriteLine(e.Message);
}
//Console.WriteLine(jsonData.drinks.Count);
//Console.WriteLine(jsonData.drinks.Count); get ammount of drinks.
Console.ReadKey();
}
//www.thecocktaildb.com/api/json/v1/1/lookup.PHP?i=15679
private static string getRequestCoctail(string coctail)
{
///api/json/v1/1/search.PHP?s=margarita
return $"GET /api/json/v1/1/search.PHP?s=godfather HTTP/1.1\r\n"
+ "Host: www.thecocktaildb.com\r\n\r\n";
}
private static string GetMetaDataCocktail(dynamic jsonData)
{
dynamic drink = jsonData.drinks[0];
return $"DrinkID : {drink.idDrink} \nDrinkName : {drink.strDrink} \nInstructions : {drink.strInstructions}";
}
private static Drink GenerateNewDrink(dynamic jsonData)
{
Console.WriteLine(jsonData.idDrink,jsonData.strDrink,jsonData.strCategory,jsonData.strInstructions);
return new Drink(jsonData.idDrink,"",jsonData.strInstructions);
}
}
}
编辑：
我添加了饮料类：
class Drink
{
public readonly string drinkId;
public readonly string strDrink;
public readonly string strCategory;
public readonly string strInstructions;
public readonly string strGlass;
public Drink(string drinkId,string strDrink,string strCategory,string strInstructions)
{
this.drinkId = drinkId;
this.strDrink = strDrink;
this.strCategory = strCategory;
this.strInstructions = strInstructions;
}
public Drink(string drinkId,string strGlass,string strInstructions)
{
this.drinkId = drinkId;
this.strDrink = strDrink;
this.strCategory = strCategory;
this.strGlass = strGlass;
this.strInstructions = strInstructions;
}
}
}
我尝试过：
http://www.thecocktaildb.com/api/json/v1/1/search.php?s=godfather
它好了5次,然后我得到了这个错误我收到的json.
第6次也很好.
http://pastebin.com/c0d29L0S(更好的格式,然后下面的粘贴)
反序列化对象时意外结束.路径’饮料[1] .strIngredient1′,第3行,第1243位.
{"drinks":[
{"idDrink":"11423","strDrink":"Godfather","strCategory":"Ordinary Drink","strAlcoholic":"Alcoholic","strGlass":"Old-fashioned glass","strInstructions":"Pour ingredients into an old-fashioned glass over ice and serve. (Bourbon may be substituted for scotch,if preferred.)","strDrinkThumb":null,"strIngredient1":"Scotch","strIngredient2":"Amaretto","strIngredient3":"","strIngredient4":"","strIngredient5":"","strIngredient6":"","strIngredient7":"","strIngredient8":"","strIngredient9":"","strIngredient10":"","strIngredient11":"","strIngredient12":"","strIngredient13":"","strIngredient14":"","strIngredient15":"","strMeasure1":"1 1\/2 oz ","strMeasure2":"3\/4 oz ","strMeasure3":" ","strMeasure4":" ","strMeasure5":" ","strMeasure6":" ","strMeasure7":" ","strMeasure8":"","strMeasure9":"","strMeasure10":"","strMeasure11":"","strMeasure12":"","strMeasure13":"","strMeasure14":"","strMeasure15":"","dateModified":null
},{"idDrink":"11538","strDrink":"J. R.'s Godfather","strInstructions":"In an old-fashioned glass almost filled with ice cubes,combine both of the ingredients. Stir to mix the flavors.","strIngredient1":
我理解为什么它现在出错,JSON无效,但这是我收到的回复.所以我用来获得响应的代码是错的..对吧？
编辑3：
相同的请求,良好的JSON响应：
现在该程序可以运行,但它是不存在的.
解决方法
我想实际问题是你没有评估HTTP响应头.
结果很可能是批量发送的,即转移编码是“分块”的,但是你天真的读者只能获得第一个块并使用它,而不是等待更多.这可能会在请求之间发生变化(例如,在直接传递时分块,在缓存后不分块,反之亦然).所以最后,不要重新发明轮子,只需使用WebClient.
Read up the RFC section 3.6.1:
3.6.1 Chunked Transfer Coding
The chunked encoding modifies the body of a message in order to
transfer it as a series of chunks,each with its own size indicator,
followed by an OPTIONAL trailer containing entity-header fields. This
allows dynamically produced content to be transferred along with the
information necessary for the recipient to verify that it has
received the full message.
当您遇到这样的问题时,请尝试将代码拆分为较小的部分,然后检查这些部分是否能够提供预期的结果.
在您的情况下,您的HTTP下载显然似乎不完整,因此您不能真正责怪JSON解析器吐出错误(因为它们是有效的).
