我已经尝试了与is_default_constructible的C 03兼容的实现:
template<class = void> struct is_default_constructible; template<> struct is_default_constructible<> { protected: // Put base typedefs here to avoid pollution struct twoc { char a,b; }; template<bool> struct test { typedef char type; }; template<class T> static T declval(); }; template<> struct is_default_constructible<>::test<true> { typedef twoc type; }; template<class T> struct is_default_constructible : is_default_constructible<> { private: template<class U> static typename test<!!sizeof(::new U())>::type sfinae(U*); template<class U> static char sfinae(...); public: static bool const value = sizeof(sfinae<T>(0)) > 1; };
当我在GCC中测试它(-std = c 03)时,它返回0,因为构造函数是不可见的:
class Test { Test(); }; int main() { return is_default_constructible<Test>::value; }
当我在Visual C中测试它时(不同的版本都有相同的行为),我回来1.
当我在Clang中测试它(也是-std = c 03)时,我得到:
error: calling a private constructor of class 'Test' template<class U> static typename test<!!sizeof(::new U())>::type sfinae(U *); ^ note: while substituting explicitly-specified template arguments into function template 'sfinae' static bool const value = sizeof(sfinae<T>(0)) > 1; ^ note: in instantiation of template class 'is_default_constructible<Test>' requested here return is_default_constructible<Test>::value; ^ error: calling a private constructor of class 'Test' template<class U> static typename test<!!sizeof(::new U())>::type sfinae(U *); ^ note: while substituting deduced template arguments into function template 'sfinae' [with U = Test] static bool const value = sizeof(sfinae<T>(0)) > 1; ^ note: in instantiation of template class 'is_default_constructible<Test>' requested here return is_default_constructible<Test>::value;
哪个编译器是正确的,为什么?