<ListOfRowIDWithListOfBooks xmlns:bpws="http://schemas.xmlsoap.org/ws/2003/03/business-process/">
  <RowIDWithListOfBooks>
    <Row_ID>ADOA-XssK</Row_ID>
    <ListOfBookInfo>
      <book>
        <BookType>Brand</BookType>
        <BookName>jon</BookName>
      </book>
      <book>
        <BookType>Brand</BookType>
        <BookName>jon</BookName>
      </book>
    </ListOfBookInfo>
  </RowIDWithListOfBooks>
</ListOfRowIDWithListOfBooks>

解决方法@H_301_17@

使用标准分组解决方案可以轻松实现此任务.不要使用单个select语句来执行众所周知会导致性能问题的语句.

注意对identity.xsl的引用只是在样式表中包含了众所周知的identity transformation模板.

[XSLT 1.0]

<xsl:stylesheet version="1.0" 
    xmlns:xsl="http://www.w3.org/1999/XSL/Transform">

    <xsl:key name="k-books" match="book" use="concat(BookType,'|',BookName)"/>

    <xsl:include href="identity.xsl"/>

    <xsl:template match="ListOfBookInfo">
        <ListOfBookInfo>
            <xsl:copy>
                <xsl:apply-templates select="book
                [generate-id()
                =generate-id(key('k-books',concat(BookType,BookName))[1])]"/>
            </xsl:copy>
        </ListOfBookInfo>
    </xsl:template>

</xsl:stylesheet>

[XSLT 2.0]

<xsl:stylesheet version="2.0" 
    xmlns:xsl="http://www.w3.org/1999/XSL/Transform">

    <xsl:include href="identity.xsl"/>

    <xsl:template match="ListOfBookInfo">
        <ListOfBookInfo>
            <xsl:for-each-group select="book" 
                group-by="concat(BookType,BookName)">
                <xsl:apply-templates select="."/>
            </xsl:for-each-group>
        </ListOfBookInfo>
    </xsl:template>

</xsl:stylesheet>