这是我的
XML文件的结构 –
@H_502_22@解决方法
<A> <Name t="Mr.">James Bond</Name> <Name t="Mr.">Allen Bond</Name> <Name t="Mr." p="X">James Bond</Name> <Name t="Mr." p="X">James Bond</Name> <Name t="Mr.">James Bond</Name> <Name t="Mrs.">James Bond</Name> <Name t="Mrs.">James Bond</Name> <Name t="Mr.">James Bond</Name> <Name t="Mrs." p="Y">James Bond</Name> <Name t="Mrs." p="Y">James Bond</Name> </A>
我期待的输出是 –
<A> <N>Allen Bond Mr - 1</N> <N>James Bond Mr - 3</N> <N>James Bond Mr,X - 2</N> <N>James Bond Mrs - 2</N> <N>James Bond Mrs,Y - 2</N> </A>
我能够得到不同的名字,但不能添加计数…
带有
group by的XQuery 3.0解决方案：
<A>{
for $name in //Name
let $full :=
if(not($name/@p)) then concat($name,' ',$name/@t)
else concat($name,$name/@t,',$name/@p)
group by $full
return <N>{$full,'-',count($name)}</N>
}</A>
与distinct-values($arg)的XQuery 1.0解决方案：
<A>{
let $names :=
for $name in //Name
return if(not($name/@p)) then concat($name,$name/@p)
for $name in distinct-values($names)
return <N>{$name,count($names[. eq $name])}</N>
}</A>
