我有下面的数据,我试图选择除RejectedRecords及其所有子节点之外的所有节点.
<?xml version="1.0" encoding="UTF-8"?>
<inmsg>
<BPDATA>
<DATE_TIME>10072014084945</DATE_TIME>
</BPDATA>
<Orders>
<Rejected>
<RejectedRecords>
<RecordNumber>1</RecordNumber>
<RecordError>State Code is invalid</RecordError>
</RejectedRecords>
<RejectedRecords>
<RecordNumber>2</RecordNumber>
<RecordError>State Code is invalid</RecordError>
</RejectedRecords>
<FileName>Foo1.txt</FileName>
<MessageType>Rejected</MessageType>
<RecordCount>2</RecordCount>
<TotalAmount>1050.01</TotalAmount>
</Rejected>
<Unrestricted>
<FileName>Foo2.txt</FileName>
<MessageType>UnrestrictedState</MessageType>
<RecordCount>2</RecordCount>
<TotalAmount>100.10</TotalAmount>
</Unrestricted>
</Orders>
<PrimaryDocument SCIObjectID="6442821469081a3a3node1"/>
</inmsg>
我已经尝试过诸如此类的一些陈述
//*/node()[not(parent::RejectedRecords) and not(self::RejectedRecords) and not(self::RecordNumber) and not(self::RecordError)] //*[not(parent::RejectedRecords) and not(self::RejectedRecords)] //*[not(descendant-or-self::RejectedRecords)]
无论我使用什么,我仍然得到RejectedRecords节点及其子节点,因为它是与Rejected节点一起进入的.我究竟做错了什么？
解决方法
此表达式选择所有节点,但不在结果集中包含任何RejectedRecords或具有RejectedRecords作为祖先的节点：
//*[not(descendant::RejectedRecords) and not(ancestor-or-self::RejectedRecords)]
以下是XPath Tester中结果的链接
