我正在使用twilio,当调用我的twilio号码时它会调用webhook,我使用lambda函数作为webhook,
twilio期待来自webhook的xml(以前称为twiml)响应,我无法从lambda函数发送xml响应
我正在使用无服务器框架
module.exports.voice = (event,context,callback) => {
console.log("event",JSON.stringify(event))
var twiml = new VoiceResponse();
twiml.say({ voice: 'alice' },'Hello,What type of podcast would you like to listen? ');
twiml.say({ voice: 'alice' },'Please record your response after the beep. Press any key to finish.');
twiml.record({
transcribe: true,transcribeCallback: '/voice/transcribe',maxLength: 10
});
console.log("xml: ",twiml.toString())
context.succeed({
body: twiml.toString()
});
};
阳明：
service: aws-nodejs
provider:
name: aws
runtime: nodejs6.10
timeout: 10
iamRoleStatements:
- Effect: "Allow"
Action: "*"
Resource: "*"
functions:
voice:
handler: handler.voice
events:
- http:
path: voice
method: post
integration: lambda
response:
headers:
Content-Type: "'application/xml'"
template: $input.path("$")
statusCodes:
200:
pattern: '.*' # JSON response
template:
application/xml: $input.path("$.body") # XML return object
headers:
Content-Type: "'application/xml'"
响应：
如果我在代码中犯了一些错误,请告诉我
还在github上创建了一个issue
谢谢,
Inzamam Malik
解决方法
你不需要乱用serverless.yml.这是一个简单的方法：
在serverless.yml中……
functions:
voice:
handler: handler.voice
events:
- http:
path: voice
method: post
(不需要响应,标题,内容类型,模板和statusCodes)
然后,您可以在函数中设置statusCode和Content-Type.
所以删除这部分……
context.succeed({
body: twiml.toString()
});
…并将其替换为：
const response = {
statusCode: 200,headers: {
'Content-Type': 'text/xml',},body: twiml.toString(),};
callback(null,response);
Lambda代理集成(默认情况下)将其组合成适当的响应.
我个人觉得这种方式更简单,更易读.
