我是
Python的新手.我想将此XML字符串显示为模板中的列表.
xmlData = """<?xml version="1.0" encoding="utf-8"?> <django-objects version="1.0"> <object model="task.task" pk="4"> <field name="name" type="CharField">New Task</field> <field name="mission_id" type="IntegerField">2</field> <field name="parent_task_id" type="IntegerField">0</field> </object> <object model="task.task" pk="5"> <field name="name" type="CharField">New Task</field> <field name="mission_id" type="IntegerField">2</field> <field name="parent_task_id" type="IntegerField">0</field> </object> <object model="task.task" pk="6"> <field name="name" type="CharField">New ask</field> <field name="mission_id" type="IntegerField">2</field> <field name="parent_task_id" type="IntegerField">0</field> </object> <object model="task.task" pk="7"> <field name="name" type="CharField">New Task</field> <field name="mission_id" type="IntegerField">2</field> <field name="parent_task_id" type="IntegerField">0</field> </object></django-objects> """
我只想将其显示为列表.
我导入cElementTree
from xml.etree import cElementTree as ET
我也做了：
xmlList = ET.fromstring(xmlData)
但我不知道如何展示它.我想展示这样的东西.
print xmlList.name print xmlList.mission_id print xmlList.parent_task_id
请帮我知道正确的语法.
解决方法
您可以使用此代码示例：
from xml.etree import cElementTree as ET
xml = ET.fromstring(xmlData)
for child in xml.iter('field'):
print child.tag,child.attrib,child.text
迭代所有名为field的XML元素,并将其标记,属性和文本值打印到控制台.
查看xml.etree documentation了解更多样品.
Django视图
为了将解析的XML数据呈现为Django应用程序中的视图,您需要@L_404_2@和template.
假设您的项目中安装了名为app的Django应用程序.
应用程序/ views.py
from xml.etree import cElementTree as ET
from django.http import HttpResponse
from django.shortcuts import render
from django.template import Context,loader
def xml_view(request):
xmlData = """<?xml version="1.0" encoding="utf-8"?>
<django-objects version="1.0">
<object model="task.task" pk="4">
<field name="name" type="CharField">foo</field>
<field name="mission_id" type="IntegerField">1</field>
<field name="parent_task_id" type="IntegerField">20</field>
</object>
<object model="task.task" pk="7">
<field name="name" type="CharField">bar</field>
<field name="mission_id" type="IntegerField">2</field>
<field name="parent_task_id" type="IntegerField">10</field>
</object></django-objects>"""
xml = ET.fromstring(xmlData)
fields = []
for obj in xml.iter("object"):
fields.append({'name': obj.find("field[@name='name']").text,'mission_id': obj.find("field[@name='mission_id']").text,'parent_task_id': obj.find("field[@name='parent_task_id']").text,})
t = loader.get_template('your_app/xml_view.html')
c = Context({'elem_list': fields})
return HttpResponse(t.render(c))
应用程序/模板/应用/ xml_view.html
<html lang="en">
<body>
<table>
<tr>
<th>Name</th>
<th>Mission ID</th>
<th>Parent Task ID</th>
</tr>
{% for elem in elem_list %}
<tr>
<td>{{ elem.name }}</td>
<td>{{ elem.mission_id }}</td>
<td>{{ elem.parent_task_id }}</td>
</tr>
{% endfor %}
</body>
</html>
