该对象需要序列化为一个非常简单的输出XML。

>最新&最大的 – 使用.Net 4 beta 2
>对象永远不需要反序列化。
> XML不应该有任何xmlns：…命名空间refs
>需要支持任何子类型的Exception和ISubObject。
>这将非常难以更改原始对象。

目的：

[Serializable] 
 class MyObj
 {
     string str;
     Exception ex;
     ISubObject subobj;
 }

需要序列化成：

<xml>
  <str>...</str>
  <ex i:nil="true" />
  <subobj i:type="Abc">
     <AbcProp1>...</AbcProp1>
     <AbcProp2>...</AbcProp2>
  </subobj>
</xml>

我使用这个代码：

private static string ObjectToXmlString(object obj)
{
    if (obj == null) throw new ArgumentNullException("obj");

    var serializer =
        new DataContractSerializer(
            obj.GetType(),null,Int32.MaxValue,false,new AllowAllContractResolver());

    var sb = new StringBuilder();
    using (var xw = XmlWriter.Create(sb,new XmlWriterSettings
    {
        OmitXmlDeclaration = true,NamespaceHandling = NamespaceHandling.OmitDuplicates,Indent = true
    }))
    {
        serializer.WriteObject(xw,obj);
        xw.Flush();

        return sb.ToString();
    }
}

从this article我采用了一个DataContractResolver，所以没有子类型必须声明：

public class AllowAllContractResolver : DataContractResolver
{
    public override bool TryResolveType(Type dataContractType,Type declaredType,DataContractResolver knownTypeResolver,out XmlDictionaryString typeName,out XmlDictionaryString typeNamespace)
    {
        if (!knownTypeResolver.TryResolveType(dataContractType,declaredType,out typeName,out typeNamespace))
        {
            var dictionary = new XmlDictionary();
            typeName = dictionary.Add(dataContractType.FullName);
            typeNamespace = dictionary.Add(dataContractType.Assembly.FullName);
        }
        return true;
    }

    public override Type ResolveName(string typeName,string typeNamespace,DataContractResolver knownTypeResolver)
    {
        return knownTypeResolver.ResolveName(typeName,typeNamespace,null) ?? Type.GetType(typeName + "," + typeNamespace);
    }
}