如何使用xslt比较和合并两个xml

我想比较两个xmls然后合并它们.例如：

myFile1.xml

<?xml version="1.0" encoding="ISO-8859-1"?>
<catalog>
<data>
    <title>Title1</title>
    <description>Description1</description>
    <myid>1</myid>
</data>
<data>
    <title>Title2</title>
    <description>Description2</description>
    <myid>2</myid>
</data>
</catalog>

myFile2.xml

<?xml version="1.0" encoding="ISO-8859-1"?>
<catalog>
<data>
    <title>Title1</title>
    <description>Description1</description>
    <author>Author1</author>
    <date>12/34/5678</date>
    <myid>1</myid>
</data>
<data>
    <author>Author2</author>
    <date>87/65/4321</date>
    <myid>2</myid>
</data>
</catalog>

期望的输出：

<?xml version="1.0" encoding="ISO-8859-1"?>
<catalog>
<data>
    <title>Title1</title>
    <description>Description1</description>
    <myid>1</myid>
    <author>Author1</author>
    <date>12/34/5678</date>
</data>
<data>
    <title>Title2</title>
    <description>Description2</description>
    <myid>2</myid>
    <author>Author2</author>
    <date>87/65/4321</date>
</data>
</catalog>

我有一个代码,但它没有按照所需的输出执行.

<?xml version="1.0" encoding="ISO-8859-1"?>
<xsl:transform version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:output method="xml" version="1.0" encoding="ISO-8859-1" indent="yes"/>
<xsl:variable name="compare" select="'myFile1.xml'"/>
<xsl:variable name="with" select="'myFile2.xml'"/>
<xsl:template match="@*|node()">
    <xsl:copy>
        <xsl:apply-templates select="@*|node()"/>
    </xsl:copy>
</xsl:template>
<xsl:template match="*">
    <xsl:copy>
        <xsl:apply-templates select="@*|node()"/>
        <xsl:variable name="info1" select="document($compare)/catalog/data[myid=current()/myid]/."/>
        <xsl:variable name="info2" select="document($with)/catalog/data[myid=current()/myid]/."/>
        <xsl:for-each select="$info1/*">
            <xsl:variable name="check1" select="name(current())"/>
            <!--xsl:text>Current node1 : </xsl:text><xsl:value-of select="$check1"/-->
            <xsl:for-each select="$info2/*">
                <xsl:variable name="check2" select="name(current())"/>
                <!--xsl:text>Current node2 : </xsl:text><xsl:value-of select="$check2"/-->
                <xsl:if test="$check1!=$check2">
                    <xsl:copy-of select="."/>
                </xsl:if>
            </xsl:for-each>
        </xsl:for-each>
    </xsl:copy>
</xsl:template>
</xsl:transform>

请帮忙！

@H_403_20@

<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform"> <xsl:output omit-xml-declaration="yes" indent="yes"/> <xsl:strip-space elements="*"/> <xsl:variable name="catalog2" select="document('source_test2.xml')/catalog"/> <xsl:template match="catalog"> <catalog> <xsl:apply-templates select="data"/> </catalog> </xsl:template> <xsl:template match="data"> <xsl:variable name="data2" select="$catalog2/data[myid=current()/myid]/."/> <data> <xsl:choose> <xsl:when test="title"> <xsl:copy-of select="title"/> </xsl:when> <xsl:otherwise> <xsl:copy-of select="$data2/title"/> </xsl:otherwise> </xsl:choose> <xsl:choose> <xsl:when test="description"> <xsl:copy-of select="description"/> </xsl:when> <xsl:otherwise> <xsl:copy-of select="$data2/description"/> </xsl:otherwise> </xsl:choose> <xsl:copy-of select="myid"/> <xsl:choose> <xsl:when test="author"> <xsl:copy-of select="author"/> </xsl:when> <xsl:otherwise> <xsl:copy-of select="$data2/author"/> </xsl:otherwise> </xsl:choose> <xsl:choose> <xsl:when test="date"> <xsl:copy-of select="date"/> </xsl:when> <xsl:otherwise> <xsl:copy-of select="$data2/date"/> </xsl:otherwise> </xsl:choose> </data> </xsl:template> </xsl:stylesheet>

如何使用xslt比较和合并两个xml

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