如何用jQuery读取这个XML文件？
对于“普通标签”,没有问题,例如：< car> Mustang< / car>
对于“普通标签”,没有问题,例如：< car> Mustang< / car>
HTML / jQuery的：
$(document).ready(function(){
$.get("AMA.xml",function(XMLArray){
$(XMLArray).find("dataset").each(function(){
var $myAMA = $(this);
var number = $myAMA.attr("article.plunumber");
var name = $myAMA.attr("article.name");
var price = $myAMA.attr("article.price").text();
$("#AMAContainer").append("<p>"+number+"<br>"+name+"<br>"+price+"</p>");
});
});
});
XML文件：
<document name="screen">
<section name="list">
<dataset>
<var key="type">article</var>
<var key="article.number">1</var>
<var key="article.name">Testname1</var>
<var key="article.displayname"/>
<var key="article.price">99,99</var>
<var key="article.plunumber">1</var>
<action key="STANDARD">bp1;</action>
</dataset>
<dataset>
<var key="type">article</var>
<var key="article.number">2</var>
<var key="article.name">Testname2</var>
<var key="article.price">88,88</var>
<var key="article.plunumber">2</var>
<action key="STANDARD">bp2;</action>
</dataset>
</section>
</document>
我绝对不知道如何读取这些值.
我只需要三个(数字,名称,价格).
您可以按属性选择元素,只需使用属性选择器或filter()函数等.
$(document).ready(function () {
$.get("AMA.xml",function (XMLArray) {
var xml = $.parseXML(XMLArray);
$(xml).find("dataset").each(function () {
var number = $('[key="article.plunumber"]',this).text();
var name = $('[key="article.name"]',this).text();
var price = $('[key="article.price"]',this).text();
$("#AMAContainer").append("<p>" + number + "<br>" + name + "<br>" + price + "</p>");
});
});
});
