我有一个相当复杂的xslt表使用模板将一个xml格式转换为另一个xml格式.但是,在生成的xml中,我需要排除所有空元素.怎么做的?
这就是基础xslt的样子:
<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform" xmlns:far="http://www.itella.com/fargo/fargogate/" xmlns:a="http://tempuri.org/XMLSchema.xsd" xmlns:p="http://tempuri.org/XMLSchema.xsd"> <xsl:import href="TransportCDMtoFDM_V0.6.xsl"/> <xsl:import href="ConsignmentCDMtoFDM_V0.6.xsl"/> <xsl:template match="/"> <InboundFargoMessage> <EdiSender> <xsl:value-of select="TransportInformationMessage/SenderId"/> </EdiSender> <EdiReceiver> <xsl:value-of select="TransportInformationMessage/RecipientId"/> </EdiReceiver> <EdiSource> <xsl:value-of select="TransportInformationMessage/Waybill/Parties/Consignor/Id"/> </EdiSource> <EdiDestination>FARGO</EdiDestination> <Transportations> <xsl:for-each select="TransportInformationMessage/TransportUnits/TransportUnit"> <xsl:call-template name="transport"/> </xsl:for-each> <xsl:for-each select="TransportInformationMessage/Waybill/TransportUnits/TransportUnit"> <xsl:call-template name="transport"/> </xsl:for-each> <xsl:for-each select="TransportInformationMessage/Waybill"> <EdiImportTransportationDTO> <Consignments> <xsl:for-each select="Shipments/Shipment"> <xsl:call-template name="consignment"/> </xsl:for-each> </Consignments> <EdiTerminalDepartureTime> <xsl:value-of select="DatesAndTimes/EstimatedDepartureDateTime"/> <xsl:value-of select="DatesAndTimes/DepartureDateTime"/> </EdiTerminalDepartureTime> <EdiAgentTerminalArrivalDate> <xsl:value-of select="DatesAndTimes/EstimatedArrivalDateTime"/> <xsl:value-of select="DatesAndTimes/ArrivalDateTime"/> </EdiAgentTerminalArrivalDate> <EdiActivevehicle> <xsl:value-of select="Vehicle/TransportShiftNumber"/> </EdiActivevehicle> <EdiConveyerZipCodeTown><xsl:text> </xsl:text></EdiConveyerZipCodeTown> </EdiImportTransportationDTO> </xsl:for-each> </Transportations> </InboundFargoMessage> </xsl:template> </xsl:stylesheet>
需要添加什么,以便省略空元素?
例如,生成的xml中的片段:
<?xml version="1.0" encoding="UTF-8"?> <InboundFargoMessage xmlns:p="http://tempuri.org/XMLSchema.xsd" xmlns:far="http://www.itella.com/fargo/fargogate/" xmlns:a="http://tempuri.org/XMLSchema.xsd"> <EdiSender>XXXX</EdiSender> <EdiReceiver>YYYY</EdiReceiver> <EdiSource>TR/BAL/IST</EdiSource> <EdiDestination>FARGO</EdiDestination> <Transportations> <EdiImportTransportationDTO> <Consignments> <EdiImportConsignmentDTO> <ConsignmentLines> <EdiImportConsignmentLineDTO> <DangerousGoodsItems> <EdiImportDangerGoodsItemDTO> <EdiKolliTypeOuter/> <EdiKolliTypeInner/> <EdiTechnicalDescription/> <EdiUNno/> <EdiClass/> <EdiDangerFactor/> <EdiEmergencyTemperature/> </EdiImportDangerGoodsItemDTO> </DangerousGoodsItems> <BarCodes> <EdiImportConsignmentLineBarcodeDTO/> </BarCodes> <EdiNumberOfPieces>00000002</EdiNumberOfPieces> <EdiGrossWeight>0.000</EdiGrossWeight> <EdiHeight/> <EdiWidth/> <EdiLength/> <EdiGoodsDescription/> <EdiMarkingAndNumber/> <EdiKolliType>road</EdiKolliType> <EdiCbm/> <EdiLdm/> </EdiImportConsignmentLineDTO>
这真的需要:
<?xml version="1.0" encoding="UTF-8"?> <InboundFargoMessage xmlns:p="http://tempuri.org/XMLSchema.xsd" xmlns:far="http://www.itella.com/fargo/fargogate/" xmlns:a="http://tempuri.org/XMLSchema.xsd"> <EdiSender>XXXX</EdiSender> <EdiReceiver>YYYY</EdiReceiver> <EdiSource>TR/BAL/IST</EdiSource> <EdiDestination>FARGO</EdiDestination> <Transportations> <EdiImportTransportationDTO> <Consignments> <EdiImportConsignmentDTO> <ConsignmentLines> <EdiImportConsignmentLineDTO> <DangerousGoodsItems/> <BarCodes/> <EdiNumberOfPieces>00000002</EdiNumberOfPieces> <EdiGrossWeight>0.000</EdiGrossWeight> <EdiKolliType>road</EdiKolliType> </EdiImportConsignmentLineDTO>
换句话说:应该省略空元素.
提供的(部分)XSLT代码很好地说明了XSLT反模式.几乎总是尝试避免使用< xsl:for-each>.
下面是一个示例XML文档和一个转换,它复制除“空”元素之外的所有节点.这里的“空”是指无子女,或者只有一个子空白子节点.
XML文档:
<a> <b> <c> </c> <d/> <e>1</e> </b> </a>
转型:
<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform"> <xsl:output omit-xml-declaration="yes" indent="yes"/> <xsl:strip-space elements="*"/> <xsl:template match="node()|@*"> <xsl:copy> <xsl:apply-templates select="node()|@*"/> </xsl:copy> </xsl:template> <xsl:template match= "*[not(node())] | *[not(node()[2]) and node()/self::text() and not(normalize-space()) ] "/> </xsl:stylesheet>
结果:
<a> <b> <e>1</e> </b> </a>
请注意:
>使用身份规则.
>我们如何使用仅匹配“空”元素的模板覆盖标识规则.由于此模板不执行任何操作(根本没有主体),因此不会复制(“删除”)“空”元素.
使用和覆盖标识规则是最重要的XSLT设计模式.