我创建了一个
XML Doc,并希望引用XSLT文件.
//<?xml-stylesheet type="text/xsl" href="OBReport.xslt"?>
这个XML生成：
XElement xml = new XElement("ReportedOn",from dl in EL.DocumentLog.ToList()
join o in EL.Organization
on dl.OrganizationID equals o.OrganizationId
where dl.ActionDate >= stDate &
dl.ActionDate <= enDate
orderby dl.DefendantName,dl.DocumentName
select new XElement("persons",new XAttribute("documentName",dl.DocumentName),new XElement("defendantName",dl.DefendantName),new XElement("actionDate",dl.ActionDate.ToString()),new XElement("startDate",dl.StartDate.ToString()),new XElement("endDate",dl.EndDate.ToString()),new XElement("organizationName",o.OrganizationName) ));
添加
XProcessingInstruction元素.
原文链接：https://www.f2er.com/xml/292644.html而不是你的XElement(可以用作文档,但有限制),而不是包围XDocument.所以,在您的代码之后：
XElement body = ...; // root XElement from your Linq statement
XDocument doc = new XDocument(
new XProcessingInstruction("xml-stylesheet","type='text/xsl' ref='hello.xsl'"),body);
