[Serializable]
public class Base
{

    public string Property1 { get; set; }
    public int Property2 { get; set; }
}

[Serializable]
public class Sub: Base
{
    public List<string> Property3 { get; set; }

    public Sub():base()
    {
        Property3 = new List<string>();
    }        
}

我将它们像这样序列化：

Sub s = new Sub {Property1 = "subtest",Property2 = 1000};
s.Property3.Add("item 1");
s.Property3.Add("item 2");

XmlSerializer sFormater = new XmlSerializer(typeof(Sub));
using (FileStream fStream = new FileStream("SubData.xml",FileMode.Create,FileAccess.Write,FileShare.None))
{
    sFormater.Serialize(fStream,s);
}

我如何反序列化他们,以便我回到正确的班级？

像我一样,我想要这样的东西

XmlSerializer bFormater = new XmlSerializer(typeof (Base));
Base newBase;
using (FileStream fStream = new FileStream("BaseData.xml",FileMode.Open,FileAccess.Read,FileShare.Read))
{
    newBase = (Base) bFormater.Deserialize(fStream);
}

除了我可以传递任何从Base下降的类的XML文件,并且将创建正确的类.

我想我可以读取XML的根节点的名称,并使用switch语句创建正确的XmlSerializer,但是我想知道是否有一个更简单的方法.