我有2个xml文件,我需要使用样式表合并在一起
<AssessmentInput> <ApplicationData>...</AppicationData> <MetricList>...</MetricList> </AssessmentInput>
一个是ApplicationData,另一个是MetricList.
这就是我所做的,但它与应有的无关
<?xml version="1.0" encoding="ascii"?>
<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform" xmlns:exslt="http://exslt.org/common" exclude-result-prefixes="xsl exslt">
<xsl:output omit-xml-declaration="yes" method="xml" encoding="UTF-8"/>
<xsl:param name="ApplicationData" select="/"/>
<xsl:param name="MetricList"/>
<xsl:template match="/">
<xsl:apply-templates select="$ApplicationData/ApplicationData"/>
</xsl:template>
<xsl:template match="ApplicationData">
<xsl:copy>
<xsl:apply-templates select="@*"/>
<xsl:apply-templates select="*"/>
</xsl:copy>
</xsl:template>
<xsl:template match="@* | node()">
<xsl:copy>
<xsl:apply-templates select="@* | node()"/>
</xsl:copy>
</xsl:template>
</xsl:stylesheet>
请帮我.我对XSLT没有任何经验.
给定以下输入文件：
原文链接：https://www.f2er.com/xml/292125.htmlApplicationData.xml
<?xml version="1.0" ?>
<ApplicationData>
Whatever data you have in here.
</ApplicationData>
MetricList.xml
<?xml version="1.0" ?>
<MetricList>
Whatever list you have in here.
</MetricList>
AssessmentInput.xml
<?xml version="1.0" ?> <AssessmentInput />
以下转换merge.xsl应用于AssessmentInput.xml
<?xml version="1.0" ?>
<xsl:transform
xmlns:xsl="http://www.w3.org/1999/XSL/Transform"
version="1.0">
<xsl:template match="/AssessmentInput">
<xsl:copy>
<xsl:copy-of select="document('ApplicationData.xml')" />
<xsl:copy-of select="document('MetricList.xml')" />
</xsl:copy>
</xsl:template>
</xsl:transform>
产生正确的输出
<?xml version="1.0" encoding="UTF-8"?>
<AssessmentInput>
<ApplicationData>
Whatever data you have in here.
</ApplicationData>
<MetricList>
Whatever list you have in here.
</MetricList>
</AssessmentInput>
