我需要在我的
Spring Boot应用程序中添加一个监听器,在web.xml中看起来像
<listener>
<listener-class>
org.springframework.web.context.request.RequestContextListener
</listener-class>
</listener>
我使用no-web.xml配置,所以我有一个类似的
public class AppFilterConfig extends AbstractAnnotationConfigDispatcherServletInitializer {
@Override
protected Filter[] getServletFilters() {
CharacterEncodingFilter filter = new CharacterEncodingFilter();
filter.setEncoding("UTF8");
filter.setForceEncoding(true);
Filter[] filters = new Filter[1];
filters[0] = filter;
return filters;
}
private int maxUploadSizeInMb = 5 * 1024 * 1024; // 5 MB
@Override
protected Class<?>[] getRootConfigClasses() {
return null;
}
@Override
protected Class<?>[] getServletConfigClasses() {
return null;
}
@Override
protected String[] getServletMappings() {
return new String[]{"/"};
}
@Override
protected void registerDispatcherServlet(ServletContext servletContext) {
super.registerDispatcherServlet(servletContext);
servletContext.addListener(new HttpSessionEventPublisher());
}
@Override
public void onStartup(ServletContext servletContext) throws ServletException {
super.onStartup(servletContext);
servletContext.addListener(new RequestContextListener());
}
}
从上面的代码可以看出,我已经为onStartup(ServletContext servletContext)方法添加了一个监听器,但它仍然没有帮助,因为我仍然得到
In this case,use RequestContextListener or RequestContextFilter to expose the current request.
这条信息.如何正确地将侦听器添加到Spring Boot应用程序中？
我创建了这个类,这解决了我的问题.
原文链接：https://www.f2er.com/xml/292007.html@Configuration
@WebListener
public class MyRequestContextListener extends RequestContextListener {
}
