如何制作它以便当我在XCode中按一个按钮时,其余按钮(包括按下的按钮)将被禁用？当然我仍然希望通过按下按钮来执行该功能.我只是不希望用户能够多次按任何按钮,也不希望他们在按下第一个按钮之后再按下另一个按钮.以下是我在这种情况下的两个按钮的IBActions：
@IBAction func addVote1(sender: AnyObject) {
var query = PFQuery(className: "VoteCount")
query.getObjectInBackgroundWithId("BiEM17uUYT") {
(voteCount1: PFObject!,error: NSError!) ->Void in
if error != nil {
NSLog("%@",error)
} else {
voteCount1.incrementKey("votes")
voteCount1.saveInBackgroundWithTarget(nil,selector: nil)
}
let votes = voteCount1["votes"] as Int
let votes2 = voteCount1["votes2"] as Int
self.pollResults1.text = "\(votes) votes \(votes2) votes"
}
}
@IBAction func addVote2(sender: AnyObject) {
var query = PFQuery(className: "VoteCount")
query.getObjectInBackgroundWithId("BiEM17uUYT") {
(voteCount1: PFObject!,error: NSError!) -> Void in
if error != nil {
NSLog("%@",error)
} else {
voteCount1.incrementKey("votes2")
voteCount1.saveInBackgroundWithTarget(nil,selector: nil)
}
let votes = voteCount1["votes"] as Int
let votes2 = voteCount1["votes2"] as Int
self.pollResults2.text = "\(votes) votes \(votes2) votes"
}
}
}
解决方法
如果尚未设置按钮的@IBOutlet属性,则添加按钮的延迟var数组.在按钮处理程序中,将每个按钮的enabled属性设置为false.
class ViewController {
@IBOutlet var button1: UIButton!
@IBOutlet var button2: UIButton!
lazy var buttons: [UIButton] = [self.button1,self.button2]
// ...
@IBAction func addVote1(sender: AnyObject) {
for button in self.buttons {
button.enabled = false
}
// ...
}
}